{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

07-02ChapGere.0009 - stresses Show all results on sketches...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
SECTION 7.4 Mohr’s Circle for Plane Stress 447 (b) P RINCIPAL STRESSES 2 p 44.93 and p 22.46 2 p 135.07 and p 67.54 For 2 p 44.93 : For 2 p 135.07 : Therefore, 1 26.3 MPa and 2 84.7 MPa and u p 2 22.46 u p 1 67.54 s x 1 26.3 MPa s x 1 84.7 MPa s x 1 s x s y 2 s x s y 2 cos 2 u t xy sin 2 u tan 2 u p 2 t xy s x s y 0.99746 x O p 1 67.54 84.7 MPa 26.3 MPa y Mohr’s Circle for Plane Stress The problems for Section 7.4 are to be solved using Mohr’s circle. Consider only the in-plane stresses (the stresses in the xy plane). Problem 7.4-1 An element in uniaxial stress is subjected to tensile stresses x 14,500 psi, as shown in the figure. Using Mohr’s circle, determine (a) the stresses acting on an element oriented at a counterclockwise angle 24° from the x axis and (b) the maximum shear stresses and associated normal
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: stresses. Show all results on sketches of properly oriented elements. Solution 7.4-1 Uniaxial stress y x O 14,500 psi s x 5 14,500 psi s y 5 t xy 5 (a) E LEMENT AT u 5 24 8 (All stresses in psi) 2 u 5 48 8 u 5 24 8 R 5 7250 psi Point C : s x 1 5 7250 psi Point D : Point D 9 : t x 1 y 1 5 5390 psi s x 1 5 R 2 R cos 2 u 5 2400 psi t x 1 y 1 5 R sin 2 u 5 2 5390 psi s x 1 5 R 1 R cos 2 u 5 12,100 psi D' D ( u 5 24 8 ) A ( u 5 0) 14,500 2 u 2 u s 2 2 u s 1 = ] 90 8 C S 1 S 2 R R O B ( u 5 90 8 ) s x 1 t x 1 y 1 x O 5390 psi u 5 24 8 2400 psi 12,100 psi y D' D } A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
View Full Document

{[ snackBarMessage ]}