07-03ChapGere.0012 - A-PDF Split DEMO : Purchase from...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Hooke’s Law for Plane Stress When solving the problems for Section 7.5, assume that the material is linearly elastic with modulus of elasticity E and Poisson’s ratio n . Problem 7.5-1 A rectangular steel plate with thickness t 5 0.25 in. is subjected to uniform normal stresses s x and s y , as shown in the figure. Strain gages A and B , oriented in the x and y directions, respectively, are attached to the plate. The gage readings give normal strains e x 5 0.0010 (elongation) and e y 52 0.0007 (shortening). Knowing that E 5 30 3 10 6 psi and n 5 0.3, determine the stresses s x and s y and the change D t in the thickness of the plate. Solution 7.5-1 Rectangular plate in biaxial stress SECTION 7.5 Hooke’s Law for Plane Stress 463 s y s x y x O B A t 5 0.25 in. « x 5 0.0010 « y 52 0.0007 E 5 30 3 10 6 psi ±5 0.3 Substitute numerical values: Eq. (7-40a): s x 5 E (1 2 n 2 ) ( e x 1 ne y ) 5 26,040 psi Eq. (7-40b): Eq. (7-39c): D t 5 « z t 52 32.1 3 10 2 6 in. (Decrease in thickness)
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Institute of Technology.

Ask a homework question - tutors are online