07-03ChapGere.0012

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Hooke’s Law for Plane Stress When solving the problems for Section 7.5, assume that the material is linearly elastic with modulus of elasticity E and Poisson’s ratio n . Problem 7.5-1 A rectangular steel plate with thickness t 5 0.25 in. is subjected to uniform normal stresses s x and s y , as shown in the figure. Strain gages A and B , oriented in the x and y directions, respectively, are attached to the plate. The gage readings give normal strains e x 5 0.0010 (elongation) and e y 52 0.0007 (shortening). Knowing that E 5 30 3 10 6 psi and n 5 0.3, determine the stresses s x and s y and the change D t in the thickness of the plate. Solution 7.5-1 Rectangular plate in biaxial stress SECTION 7.5 Hooke’s Law for Plane Stress 463 s y s x y x O B A t 5 0.25 in. « x 5 0.0010 « y 52 0.0007 E 5 30 3 10 6 psi ±5 0.3 Substitute numerical values: Eq. (7-40a): s x 5 E (1 2 n 2 ) ( e x 1 ne y ) 5 26,040 psi Eq. (7-40b): Eq. (7-39c): D t 5 « z t 52 32.1 3 10 2 6 in. (Decrease in thickness)
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## This note was uploaded on 09/20/2009 for the course COE 3001 taught by Professor Armanios during the Spring '08 term at Georgia Institute of Technology.

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