{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

07-03ChapGere.0013

07-03ChapGere.0013 - Solve the preceding problem for a...

This preview shows page 1. Sign up to view the full content.

Solution 7.5-3 Plane stress 464 CHAPTER 7 Analysis of Stress and Strain Given: x , y , (a) N ORMAL STRAIN z Eq. (7-34c): Eq. (7-36a): Eq. (7-36b): Substitute x and y into the first equation and simplify: e z n 1 n ( e x e y ) s y E (1 n 2 ) ( e y ne x ) s x E (1 n 2 ) ( e x ne y ) e z n E ( s x s y ) (b) D ILATATION Eq. (7-47): Substitute x and y from above and simplify: e 1 2 n 1 n ( e x e y ) e 1 2 n E ( s x s y ) Problem 7.5-4 A magnesium plate in biaxial stress is subjected to tensile stresses x 24 MPa and y 12 MPa (see figure). The corresponding strains in the plate are x 440 10 6 and y 80 10 6 . Determine Poisson’s ratio and the modulus of elasticity E for the material. y x y x O Solution 7.5-4 Biaxial stress x 24 MPa y 12 MPa x 440 10 6 y 80 10 6 P OISSON S RATIO AND MODULUS OF ELASTICITY Eq. (7-39a): Eq. (7-39b): e y 1 E ( s y ns x ) e x 1 E ( s x ns y ) Substitute numerical values: E (440 10 6 ) 24 MPa (12 MPa) E (80 10 6 ) 12 MPa
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Solve the preceding problem for a steel plate with s x 5 10,800 psi (tension), s y 5 2 5400 psi (compression), e x 5 420 3 10 2 6 (elongation), and e y 5 2 300 3 10 2 6 (shortening). Solution 7.5-5 Biaxial stress s x 5 10,800 psi s y 5 2 5400 psi « x 5 420 3 10 2 6 « y 5 2 300 3 10 2 6 P OISSON ’ S RATIO AND MODULUS OF ELASTICITY Eq. (7-39a): Eq. (7-39b): e y 5 1 E ( s y 2 ns x ) e x 5 1 E ( s x 2 ns y ) Substitute numerical values: E (420 3 10 2 6 ) 5 10,800 psi 2 ± ( 2 5400 psi) E ( 2 300 3 10 2 6 ) 5 2 5400 psi 2 ± (10,800 psi) Solve simultaneously: ± 5 1/3 E 5 30 3 10 6 psi Probs. 7.5-4 through 7.5-7 A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
View Full Document

{[ snackBarMessage ]}