Unformatted text preview: 2) The conductivity of a metal decreases when temperature is increased while the conductivity of an intrinsic semiconductor increases because of the thermal affect; metals are great conductors of heat with a large number of free electrons, making it harder and harder to conduct electricity as the temperature is increased. 3) A) n = 1.3N Ag = 1.3(10.5)(6.023*10 23 )/107.87 = 7.62E22 cm-3 = 7.62E28 m-3 B) μ e = σ/ (n|e|) = 6.8E7/(7.62E28*1.602E-19) = 5.57E-3 m 2 /V-s 4) A) n = ( σ-p|e| μ h )/(|e| μ e ) = [5.93E-3 – (7E17)(1.602E-19)(0.05)]/(1.602E-19 *0.14) = 2.5E17m-3 B) p-type extrinsic because p is greater than n 5) σ = n|e| μ e = 5E17(1.602E-19)(350/1000) = 0.028035(omega-m)-1 6) A) metal electrical insulator undoped semiconductor donor doped semiconductor B)...
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- Spring '07
- Solubility, Condensed matter physics, Extrinsic semiconductor, precipitation heat treatment