{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Electrical Engineering 42 - Spring 2001 - Oldham - Midterm 1

Electrical Engineering 42 - Spring 2001 - Oldham - Midterm...

Info iconThis preview shows pages 1–9. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 6
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 8
Background image of page 9
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: WIVERSITY OF CALIFORNM College of Engineering Department of Electrical Engineering and Computer Sciences Professor Oldham Spring 2001 EECS 42 — MIDTERM #1 22 February 2001 Name: 6??? +£5.53" a Student ID: Last, First Signature: S O L U j / O A/ 3 Guidelines: Closed book. A 2-page summary sheet with formulas is provided at the end of the exam. Show all your work and reasoning on the exam in order to receive credit. Warning: Some problems will be graded with no partial credit, so check your answers. You may use a calculator. Do not unstaple the exam. 99:“??? This exam contains 5 problems worth 20 points each, and corresponding worksheets plus the cover page and the 2-page summary sheet. 7. Please do not ask questions except to point out possible errors or typographical mistakes. Points Your Possible Problem 1 [20 points! In the circuit below we are interested in the voltage at nodes X and Y and use nodal analysis. (3) Some possible nodal equations are given below. Circle the equation that is correct. (If none are correct, then correct one and circle it.) (21.2) Vl/R1+ V3/R4 = 0 (3.4) Vl/Rl +1; —V}££§g‘+l + V :_V )/R4 = 0 .4...m—.._., ._ ._....— 4....»— w (b) What other equation, if any, is needed to solve for VX and VY? Write it in the box below, BUT DO NOT SOLVE for VX and V1,. Answer here —> Ver \/,2 ::*\/j Super wade moaficm (80m con/6mg m r 0» [1+1ng LagrufiLg=O :7 If» :2 Jr £33.55 OAR + V's-V“ ._ O R\ R: Rq 105 mega dr etimmaedm) (WM OPS- ; VLXZS Vx Vq"\/3 Q3 +11 E??? " ”—12 J‘- E2“ L3 1.. kui I.2 — LC Wm: MW modak €01 UOFHCM b) Avx‘x MOM-4 eqvafim #W‘ Mocha/Mp UCTI/Owefivx Vx mm vq ”\quofl up V? +0 cfct +0 \(5 ~“ Vx "\‘V2 5V3 Problem 2 120 pointsl In the circuit below, the switch is operated at r = 1 pace (in other words, the capacitor is switched from node L to node R). r = lusec X L | R 200K + 10 pF 5V (3) Find VX, the voltage at node X, for t< 1p.sec. a) VX .—_ S \/ (Note: Answer must be in the box.) (b) Find VX for r = lpsec (just after switch moves). 13) VX = O V (Note: Answer must be in the box.) (c) Find VX for r—>oc. 0) VX = I; V (Note: Answer must be in the box.) (d) Sketch neatly on the axes below a plot of VX versus time. (Warning: Neatness and accuracy will be rewarded.) CDr—dmmfimcn t (usec) Problem 2 W rksh et (CS). When Swi‘tch Is on The, keg-T Ctvcm‘i’r (3 shown an +he Véfih't: "WI" WY W: SV- (Jute no CuwvenT goes fi “WW3“ w: V€S\‘S+'ov. vac—o. ! Vx = 5V- I Lb), The VON-mole amass W cagmcx‘fiv {‘5 ““W 0- mm Germ m: Switch is vaxeok +0 We ”‘3": ’ No'h‘ce now Vx {"5 the. VQVFQ‘TQ i OLQVQS‘: Hu. CulDaLH-OV‘_ We- KWW" 3f f 5v \ I \um . VoHMfi acres) («Pack-km ecu/rt 5 ‘5 4of10 Problem 3 12!! points! Find the voltage indicated for each of the following circuits. (The answer MUST be in the box provided.) (3) Find Vm {m4 774:: KM: Wt gait; ”5.1de 59"!”- VA = lm/ A+ “Viv D M433V, 3" “2m 16:: 1:4: Min/H‘W Wm {my 79% AM MW 7:0 Aw mm Va: VA+ 161 = 3+43?V 4E. E iéI-E jf drop $6 firs/£2244 Amt/1 3 mm Weir“; ew- _ Swarm (/4534- —- CMY’Tz/lt jogger 5/0?! not Jam» 64:. I I .. .245..- . :: _...‘ {LI/:2 [/E’ 2km) 3 3‘ V (/05 {Me Gal/V V1;3 e5 19“: w/WC ' acrba’j 1946 21C 2611‘s {by m; {‘48 Vijéf 50:10 Prob] 4 20 For the circuit below, calculate the following quantities. (Note that the Sign is important and the ansWeI must appear in the box.) This is a DC, not a transient, problem. @521) P1, the VIiigvver in: )(iissipated in) resistor R1. 3 Mal/10:15 P1. = 3, 9 m W : —- —. -~ m: w -- . » R " ioK - @ PT LU f2. 4' ‘ __ 6v A. Zia :(épmqréta’) \fi/jlzlléf' L ‘— 7521 “ ”(m - :FQMtZOuie) ~ i3, (9 Mi“! (b) 1'3'2,theZ power Into (d1351pated 1n) resistorjgmemm P2 = ‘67- W CD. P: r2: QM'})Z({OOK)~L\ 1:“ thaw T: ’lfiw VUZU. . v “”2 : IOOnW WW1:QAF)(IOOK)[email protected];:L W (0014 @210: w; (MAX NLEMJ’WE :- (c) P3 , the power into capacitor (33.133 2 O W 71MB 16 a DC. We4 (L'H‘OMS 9W} Pfottflm, Steaiy Shel. (1ng Current thwujh Capac§4or P 2: 1 v ' (d) P 4 , the power into the current source. I a) F\ (S; plane/t U; be 11113.91 Jmp QCI‘OSSEZ 2.. U2 693303;“? 'thj U); O‘HAWJ’: U59 pZ1V 70f10 Problem 5 120 points! The circuit below consists of two parts: 1) a “black box” that has the nonlinear I—V characteristics shown on graph I A versus VA, and 2) a simple resistor in parallel with a current source. When the switch is open, it is obvi- ousthatVA = 0 ande = 4V. Use the load-line method to find the approximate value of VB when the switch is closed. (MORTANT: You must show your work to receive credit.) (Also note: This is a DC problem, not a transient problem.) V ' I ' I VA (V) ...
View Full Document

{[ snackBarMessage ]}