q10_key - PHY-2054C-002, Fall 2008 Instructor: Dr....

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Unformatted text preview: PHY-2054C-002, Fall 2008 Instructor: Dr. Bhattacharya Quiz #10 (KEY), Thursday, Nov 20 1. Parallel rays of green mercury light with a wavelength of 540 nm pass through a slit with a width of 0.5 mm. (a) What is the distance from the central maximum to the 2nd minimum on a screen 2.0 m away from the slit? The distance of the m-th minimum is given by ym = R m . d Here m = 1, 2 , and m = 0 corresponds to the central maximum. y2 = R 2 d =2 2 540 10-9 0.5 10-3 m = 4.32 mm (b) If the wavelength is changed to 675 nm what would be the distance between the 2nd and the 3rd minima ? Here 2 675 10-9 m = 2.7 mm . y = y3 - y2 = R = d 0.5 10-3 ...
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This note was uploaded on 09/21/2009 for the course PHY 2054 taught by Professor Zmudskyy during the Fall '08 term at University of Central Florida.

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