This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: (i) No, events A and B are not mutually exclusive because both events contain the outcome (G, G, G). (j) Yes, events B and C are mutually exclusive because the two events have no outcomes in common. 6. (a) We list here the pairs of bolts using their numbers, these are equaly likely outcomes S={(1, 2) (1, 3) (1, 4) (2,1) (2, 3) (2, 4) (3, 1) (3, 2) (3, 4) (4, 1) (4, 2) (4, 3)} Hence, the probability of each outcome is 1/12. (b) P (both are 7mm) = P{(3, 4) or (4, 3)}= 2/12= 1/6 (c) P (one is 5mm and one is 7mm) = P{(1, 3) (1, 4) (2, 3) (2, 4) (3, 1) (3, 2) (4, 1) (4, 2 )} = 8/12= 2/3. 8. (a) False (b) True (c) True. All answers are explained by the frequency interpretation of probability. 10. (a) P ( E U T ) = P (E) + P (T) – P (E n T)= 0.11 (b) P ( E c U T c ) = 1  P ( E U T ) = 1  0.11 = 0.89 (c) Need to find P ( E n T c ). We know by looking at a Venn diagram that P (E)= P (E n T) + P ( E n T c ). We are given that P (E) = 0.10 and P (E n T) = 0.01. Therefore, P ( E n T c ) = 0.09....
View
Full Document
 Fall '09
 Zaliapin
 Math, Probability, Outcome, Homework Solutions Homework, likely outcomes S=

Click to edit the document details