EECS314 Hmwk1 Soln - EECS 314 Fall 2008 Homework set 1...

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EECS 314 Fall 2008 Homework set 1 Student’s name ___________________________ Discussion section # _______ (Last, First, write legibly, use ink) (use ink) Instructor is not responsible for grading and entering scores for HW papers lacking clear information in the required fields above Scores for the HW set: Problem 1 2 3 4 5 6 7 Total S c o r e Problem 1 KCL, KVL, and the Passive Sign Convention Part 1 2 3 Total Score The Assignment Consider the circuit shown on this diagram. Note that nodes A, C and B are all connected with wires thus they are in fact one node! Some currents and some voltages in the circuit are given in the table below and on the diagrams on the following page; your challenge is to calculate the unknown voltages and currents, as well as the power absorbed by each element. Element 1 2 3 4 5 6 7 Current through 24 A 2 A 18A 3 A 15 A 16A 26A Voltage across 25V 9V -2V 18 V -18V 16 V 25 V Power absorbed 600W 18W -36W 54W 270W -256W -650W © 2008 Alexander Ganago Page 1 of 7 Solution by Hongwei Liao
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EECS 314 Fall 2008 Homework set 1 Student’s name ___________________________ Discussion section # _______ (Last, First, write legibly, use ink) (use ink) Instructor is not responsible for grading and entering scores for HW papers lacking clear information in the required fields above Part 1 (10 points) Currents through 4 elements out of 7 are given (see the diagram below, on the right). Use KCL to calculate the unknown currents. Record your results in the table above (do not omit the units of measure). Choose the signs according to your reference marks. Show the magnitudes and directions of all currents on the diagram below. For your convenience, the diagram is repeated. Solution: Fig.1. Part 1, Problem 1 As shown in Fig.1, the unknown currents are denoted by 3 I , 6 I , 7 I , CB I , and AC I . (1) Apply KCL to node D, we have the following equation: 3 31 5 I AA = + Thus, 3 18 I A = . (2) Apply KCL to node E, we have the following equation: 63 2 AI I + = 3 18 I A = 6 , which is obtained above, 16 I A = As . (3) Apply KCL to node B, we have the following equation: © 2008 Alexander Ganago Page 2 of 7 Solution by Hongwei Liao
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EECS 314 Fall 2008 Homework set 1 Student’s name ___________________________ Discussion section # _______ (Last, Firs (use ink) not responsible for grading and entering scores for HW papers lacking clear inform © 2008 Alexander Ganago Page 3 of 7 Solution by Hongwei Liao 6 15 CB AI I t, write legibly, use ink) Instructor is ation in the required fields above + = 6 16 I A = , which is obtained above, 1 CB I A = As . (4) Apply KCL to node F, we have the following equation: I 7 24 2 AA = + 7 26 I A = 7 AC CB . Thus, (5) Apply KCL to node C, we have the following equation: I II = + 1 CB As I A = 7 26 and I A = 27 AC , I A = .
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EECS 314 Fall 2008 Homework set 1 Student’s name ___________________________ Discussion section # _______ (Last, First, write legibly, use ink) (use ink) Instructor is not responsible for grading and entering scores for HW papers lacking clear information in the required fields above Problem 1 Part 2 (15 points) Voltages across 3 elements out of 7 are given on the diagram.
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EECS314 Hmwk1 Soln - EECS 314 Fall 2008 Homework set 1...

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