EECS314 Hmwk9 Soln

# EECS314 Hmwk9 Soln - Homework 9 Problem 2 Part 1(1 Every second for each channel the memory required is 16 44000 704000 bits = 88000 Bytes(2 Every

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Homework 9 Solution by Hongwei Liao Problem 2 Part 1 (1) Every second, for each channel, the memory required is: 16 44000 704000  bits = 88000 Bytes (2) Every second, for two channels, the memory required is: 88000 2 176000 Bytes For every minute of music, the memory required is: 176000 60 10560000 Bytes = 10.56 MB (3) The song lasts 3 minutes 25 seconds = 205 seconds, and the memory required is: 176000 205 36080000 Bytes = 36.08 MB (1a) (4) The minutes of music can be stored on the CD: 6 700 10 3977.27 176000 T  seconds = 66.29 minutes (1b) (5) As T<80 minutes, the music is compressed. The compression ratio is: 80 1.207 66.29 (1c) Part 2 (1) Every second, for each channel, the memory required is: 18 44000 792000 bits = 99000 Bytes (2) Every second, for two channels, the memory required is: 99000 2 198000 Bytes For every minute of music, the memory required is: 198000 60 11880000 Bytes = 11.88 MB (3) The song lasts 3 minutes 25 seconds = 205 seconds, and the memory required is: 198000 205 40590000 Bytes = 40.59 MB (2a) (4) The minutes of music can be stored on the CD: 6 700 10 3535.35 198000 T seconds = 58.92 minutes (2b) (5) As T<80 minutes, the music is compressed. The compression ratio is: 80 1.358 58.91 (2c)

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Homework 9 Solution by Hongwei Liao Part 3 bits/sample × number of samples/second × 2 channels / 1000 bits/kilobit 16 44000 2/1000 1408 kbits/sec Ratio of bit rates (CD/MP3) = 1408 11 128 Duration of MP3 music can be recorded on: 6 700 10 8 bits 43750 seconds 128000 bits/sec T   12 hours and 9.167 minutes
EECS 314 Fall 2008 Homework set 9 Student’s name ___________________________ Discussion section # _______ (Last, First, write legibly, use ink) (use ink) Instructor is not responsible for grading and entering scores for HW papers lacking clear information in the required fields above © 2008 Alexander Ganago Page 1 of 2 Problem 3 Analog-to-Digital Conversion (ADC) and Decimal-to-Binary conversion For The Big Picture, see the file Analog and Digital posted on CTools. The Assignment Part 1 (20 points) Using a temperature sensor and an 8-bit Analog-to-Digital Converter (ADC), students built a thermometer for measuring the temperature of water boiling under various pressures. The table below lists the two reference points.

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## This note was uploaded on 09/23/2009 for the course EECS EECS314 taught by Professor Ganago during the Winter '09 term at University of Michigan.

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EECS314 Hmwk9 Soln - Homework 9 Problem 2 Part 1(1 Every second for each channel the memory required is 16 44000 704000 bits = 88000 Bytes(2 Every

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