EECS 314 Fall 2006 HW 04 Problem 1
Student's name ___________________________
Discussion section # __________
(Last name, first name,
IN INK)
nd
ams,
2
ight
how your work.
The voltage source
V
S
in
series with a resistor
R
S
,
as shown on the left top a
on the center top diagr
is equivalent to the current
source
I
S
in parallel with
the same resistor
R
S
,
shown on the right top
diagram, provided that
V
S
= I
S
⋅
R
S
.
Replacing a source with its equivalent is called “source transformation”; it is a good way
to solve many circuit problems, especially the “ladder” circuits such as shown on the
bottom diagram on this page. When you apply the source transformation, it is a good idea
to redraw the circuit each time you replace a source with its equivalent.
Note that, according to KCL, a parallel
combination of current sources
I
1
and
I
2
with parallel resistors
R
1
and
R
2
is
equivalent to one current source
I
1
+I
2
and one resistor
R
1
||
R
2
.
Also, according to KVL, a series
combination of voltage sources
V
1
and
V
with series resistors
R
1
and
R
2
is
equivalent to one voltage source
V
1
+V
2
and one resistor
R
1
+R
2
.
Use the source
transformation to reduce
the circuit shown on this
diagram to its Thevenin
equivalent (top left circuit
on this page), and to its
Norton equivalent (top r
diagram on this page) .
S
Alexander Ganago
September 22, 2005

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