#Chem 162-2008 11th week recitation

#Chem 162-2008 11th week recitation - CHEMISTRY 162-2008 11...

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Unformatted text preview: CHEMISTRY 162-2008 11 th WEEK RECITATION ANNOUNCEMENTS EXAMS • Exam III April 23 rd , 9:40 PM • Solving quadratic equation NOT ruled out in exam. • Possible review session dates (probably 8-10 PM) Monday, April 14 th Tuesday, April 15 th Wednesday, April 16 th Thursday, April 17 th Monday, April 21 st Tuesday, April 22 nd ATTENDANCE • Sign in QUIZ • Pick up new and old quizzes after class. Chem 162-2008 11th week recitation 1 PLAN FOR TODAY : CHAPTER 18 - ELECTROCHEMISTRY • Oxidation-Reduction Reactions • Galvanic cells, Reduction/Oxidation potentials, Free energy Chem 162-2008 11th week recitation 2 PUT ON BOARD E o (V) F 2 + 2e- → 2F- +2.87 Ba → Ba 2+ + 2e- +3.03 Ba + F 2 → Ba 2+ + 2F- +5.90 Chem 162-2008 11th week recitation 3 Chem 162-2008 11th week recitation 4 SMALLER ATOM SMALLER ION HIGHER FIRST IONIZATION ENERGY HIGHER FIRST ELECTRON AFFINITY HIGHER ELECTRONEGATIVITY LESS METALLIC PROPERTY POOR REDUCING AGENT GOOD OXIDIZING AGENT ACIDIC OXIDES PERIODIC TABLE AND PERIODIC PROPERTIES CHAPTER 18 - ELECTROCHEMISTRY ELECTRODE REDUCTION POTENTIALS ET: Review chapter 4 fundamentals. OXLEA & REGEC; discuss oxidation in terms of reacting with electronegative oxygen; discuss oxidation and reduction in terms of oxidation number (OXION; reduction is a reduction in oxidation number). Some Selected Standard Electrode Reduction Potentials E o , volt (red’n) F 2 + 2 e-----> 2 F- +2.87 H 2 O 2 + 2 H + + 2 e-----> 2 H 2 O +1.78* MnO 4- + 8H + + 5e- → Mn 2+ + 4H 2 O +1.51 Au 3+ + 3e- ----> Au +1.50 PbO 2 + 4 H + + 2 e-----> Pb 2+ + 2 H 2 O +1.46 Cl 2 + 2 e-----> 2 Cl- +1.36 Cr 2 O 7 2- + 14 H + + 6 e-----> 2 Cr 3+ + 7 H 2 O +1.33 O 2 + 4 H + + 4 e-----> 2 H 2 O +1.23* Br 2 + 2e-----> 2Br- +1.09 Ag + + e-----> Ag +0.80 Fe 3+ + e-----> Fe 2+ +0.77 MnO 4- + 2 H 2 O + 3 e-----> MnO 2 + 4 OH- +0.60 I 2 + 2 e-----> 2 I- +0.54 Cu 2+ + 2 e-----> Cu +0.34 Cu 2+ + e-----> Cu + +0.16 2H + + 2 e-----> H 2 0.00 Fe 3+ + 3e-----> Fe-0.036 Pb 2+ + 2 e-----> Pb-0.13 Ni 2+ + 2 e-----> Ni-0.23 Cd 2+ + 2e- → Cd-0.40 Cr 3+ + e-----> Cr 2+-0.50 Zn 2+ + 2 e-----> Zn-0.76 2 H 2 O + 2 e-----> H 2 + 2 OH--0.83* Al 3+ + 3e- → Al-1.66 Mg 2+ + 2 e-----> Mg-2.37 Na + + e-----> Na-2.71 Ba 2+ + 2e- ← → Ba-2.91 Cs + + e-----> Cs-3.03 * H 2 O half-cell reactions Chem 162-2008 11th week recitation 5 REDUCTION OXIDATION BALANCING REDOX EQUATIONS (Follow rules in descending order of priority) (1) Identify pairs of substances involved in oxidation (OXLEA) and reduction...
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#Chem 162-2008 11th week recitation - CHEMISTRY 162-2008 11...

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