#Chem 162-2008 final exam + answers

#Chem 162-2008 final exam + answers - Chemistry 162/162SG...

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Chemistry 162/162SG Final Exam May 12, 2008 Student Name (Print): ____TAVSS ________________ Recitation Section Number: t Recitation Instructor: _____TAVSS __________ The exam booklet has 50 questions for credit and one additional question to check the color of your exam booklet. Please answer all 51 questions on the OpScan sheet. Use the best answer of the choices available. There is no penalty for guessing. At the end of the 3-hour exam period, please hand in only this top sheet and your OpScan form. If you finish early, please do not disturb your fellow students. A proctor will check your picture ID, OpScan form, signature and calculator during the exam. The use of calculators with permanent memories (graphing calculators), cell phones, pagers, PDAs or other electronic devices other than a basic scientific calculator is expressly forbidden. The last page of the booklet contains a periodic table along with other useful data. The use of any other notes or information on this test will be considered a violation of the Academic Honesty provisions of the student code. Exam scores will be posted as soon as possible. There is a 5 point penalty for incorrectly filling out the OpScan form. ON THE OpScan FORM (Use a #2 pencil or darker) Sec Per. Instr Sec Per. Instr 1. SIGN your name across the top of the form. 01 M3 RA 30 Th3 NM 2. Code the following information ( blacken circles) 03 M5 RA 31 Th3 ET Your Name (LAST NAME FIRST) 04 M5 NM 33 M6 RA Your RU IDNUMBER 06 W3 YS 34 M6 NM [Start under Box A and continue to Box I ] 07 W3 NM 36 W6 SM Your RECITATION SECTION NUMBER in 08 W5 SM 37 M8 SZ [Sections 01-08, code a 0 under box K ] 0S TBA AM (Please code 99) 39 W8 SZ Your EXAM FORM NUMBER under box P 11 F3 NM 17 M1 MR YS = Y. Shin, RA = R. Agarwal, AM = A. McGhan 19 M3 NM SM = S. Marvasti, SZ = S. Zbaida, NM = N. Marky 20 M3 SM MR = M. Rabeony, ET = E. Tavss 23 W1 ET Periods: 1 = 9:30-10:25, 3 = 12:15-1:10 or 12:50-1:45 25 W3 ET 5 = 3:35-4:30, 6 = 5:15-6:10, 8 = 8:25p-9:20p 26 W3 MR C162fs08v1 1
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Your EXAM FORM is C162fs08v1 2
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Your EXAM FORM is 1 Chem 162-2008 Final Exam + Answers Chapter 19 – Nuclear Chemistry Nuclear binding energy What is the binding energy per nucleon of 214 At (nuclear mass of 213.9500u)? A. 1670MeV/nucleon B. 19.61 MeV/nucleon C . 7.80 MeV/nucleon D. 9.55 MeV/nucleon E. 6.53 MeV/nucleon 214 85 At contains 129 neutrons and 85 protons. 1 1 H = 1.0073g/mol (or 1.0073 u or 1.0073 amu) 1 0 n = 1.0087g/mol (or 1.0087 u or 1.0087 amu) 85 1 1 H + 129 1 0 n = 214 85 At + mass defect (85 x 1.0073g/mol) + (129 x 1.0087g/mol) = 213.9500g/mol + mass defect 215.7430g/mol = 213.9500g/mol + mass defect mass defect = 1.7928g/mol mass defect = (1.7928g/mol)/(6.022 x 10 23 atom/mol) = 2.977 x 10 -24 g/atom mass defect= (2.977x10 -24 g/atom)/(214nucleons/atom)=1.391x10 -26 g/nucleon = 1.391 x 10 -29 kg/nucleon = mass defect/nucleon E = mc 2 E = 1.391x10 -29 kg x (3 x 10 8 m/s) 2 = 1.2519 x 10 -12 J 1.2519 x 10 -12 J x 1MeV/(1.60 x 10 -13 J) = 7.84 MeV/nucleon
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This note was uploaded on 09/23/2009 for the course CHEM 162 taught by Professor Siegal during the Spring '08 term at Rutgers.

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#Chem 162-2008 final exam + answers - Chemistry 162/162SG...

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