# CA2 - Mechanics of Materials Spring Term 2008/09 April 8...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: - Mechanics of Materials Spring Term 2008/09 April 8, 2009 Class Assignment # 2 '."'.'.'.".-7---' ' ~ H=1.6m Ll=3.0m " ;: 4~~ :2 ; : :~:ve area of cable I : A '~- C ~ !. - ..~:::=~=::-::. . ~ -- .-. TB'{Su.B FORCE IN CABLE . / . T = tensile force . . ! """'" m cable , , 'I & . \ A ~- I ~ ~ '"~ ",.- 3.0m 1.5m 1 C :veRAGE1ENSD..ESTRESSlNt~~ " P=32 T 102 kN EQUILmkruM ~~U = A = 481 mm2::; 212 MPa ~ LMA = 0 i+\A """ '" ,- -~/ T v (3.0 m) - (32 kN)(4.5 m) = ~'\\ /"j~ ( ;':;::::~" T =48kN ~ v '\ Ty Ll 3.0 m \ T:=H:=;~ \ , MEM 230 ~ Problem 1.2-10 Solve the preceding problem if the load P = 32 kN; the cable has effective cross-sectional area A = 481 mmz; the dimensions of the crane are H = 1.6 m, Ll = 3.0 m, and Lz = 1..5 m; and the cable stretches by 5.1 mm. Figure is with Frob. 1.2-9.- 5c "'- ~ H 1 ~ .. R ~ I~ i. ~-1 I. LI ~ P = ~11c:N ~ FREE-BODY DIAGRAM OF GIRDER T~ I T II ~ T = ~+"TJ = Y(90 kNf + (48 kNt = 1t1? IrN TH!~~I R ~ 4- ~ §--) " II ~ .Ifl ""-'""" ~ +- 3.4m Solution 1.2-10 Loading crane with girder and cable...
View Full Document

{[ snackBarMessage ]}

### Page1 / 4

CA2 - Mechanics of Materials Spring Term 2008/09 April 8...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online