{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# CA9 - 7—7 The be am has a rectangular cross section and...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 7—7. The be am has a rectangular cross section and is made of wood. If it is subjected to a shear of V = 4 kip, and a = 10111., determine the maximum shear stress and plot the shear—stress variation over the cross section. Sketch the result in three dimensions. Section Properties: 1 I = Tim“ 13‘) = 2312.5 in‘ Q,“ = 3714': 3.75(1.5)(m) = 231.25 in” Maximum Shear Stress.- Miximum shear stress occurs a: the point where the neutral axis passes through the section. Applying the shear formula V92... tn“ = TE. _ 4(23125) -m =0.040ks:=40.0p51 Ans 7-5. If the wide-flange beam is subjected to a shear of V = 25 kip, determine the shear force resisted by the web of the beam. Section Properties: 1 3 l J - 4 = _ —_ =568.67 12(3}(12) ”(M 10 ) m Q: 237‘ '= 55(3){1)+(o.5y+2.5)(s-y)(1) = sa.s-o.sy‘ Shear Stress: Applying the shear fomula ,- 2 I: K? = m =2.484—D.02t98y1 R 568.67“) Resultant Shear Farce: For the web Vw =J raj-1. A e [5" (2.434-0.02t9ay‘) (ndy -5in = 23.0 kip ...
View Full Document

{[ snackBarMessage ]}