{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# hw3 - IEOR 162 LINEAR PROGRAMMING(FALL 04 HOMEWORK 3...

This preview shows pages 1–2. Sign up to view the full content.

IEOR 162 LINEAR PROGRAMMING (FALL 04) HOMEWORK 3 SOLUTIONS 3.3.8. The LP is infeasible, because no points can satisfy the last two constraints. 3.3.10. Let x1 = dollars bought (for francs) and x2 = francs bought (for dollars). Then we wish to solve max z = x1 - .25x2 st x1 - .25x2 0 (dollar constraint) -3x1 + x2 0 (franc constraint) x1, x2 0 In the graph the LP's feasible region is between the lines indicated by segments AB and AC. Isoprofit lines are parallel to AB. We increase z by moving down and to right. Since AB has a larger slope than AC, we will have an unbounded LP. This is due to the inconsistency in the exchange rate in the France-USA market. Of course, such an inconsistency in the currency markets would quickly be corrected before you could make an infinite amount of money!

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
3.4.1. For i = 1, 2, 3 let x i = Tons of processed Factory i waste. Then appropriate LP is min z = 15x 1 + 10x 2 + 20x 3 s.t. .10x 1 + .20x 2 + .40x 3 30(Pollutant 1) .45x 1 + .25x 2 + .30x 3 40(Pollutant 2) x 1 0,x 2 0,x 3 0
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 2

hw3 - IEOR 162 LINEAR PROGRAMMING(FALL 04 HOMEWORK 3...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online