HW1-solution

# HW1-solution - EE456 HW1 solutions EE456 HW1 Solutions...

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Unformatted text preview: EE456 HW1 solutions EE456 HW1 Solutions Problem 1. To solve this problem, you can use graphical method and iteration (VOL=VOUT, VOH=VIN : Applying VOH to the input of an inverter yields VOL at the output and vice versa) VIN 5 0.5 4.875 0.57 VOUT 0.5 4.875 0.57 4.86 VOH = 4.86V VOL = 0.57V for VIL, VIH , slope of VTC = -1 so VIL = 2V, VIH = 3V Æ NML = VIL - VOL = 1.43V, NMH = VOH - VIH = 1.86V The gate is regenerative since slope of VTC > 1 in midsecton. Problem 2. 'Q j Q j (Vhigh )  Q j (Vlow ) Ceq Vhigh  Vlow 'VD Qj § NAND AD ¨ 2H si q ¨ NA  ND © · ¸ Io  Vo ¸ ¹ ·1 ¸ ¸I ¹o AD 2 H si q N AND NA  ND 1 Io  Vo C j0 §1 NAND AD ¨ H si q ¨2 N A  ND © AD NN 1 H si q A D 2 NA  ND Io N AND NA  ND (1) Ceq § NAND  ¨ AD 2 H si q ¨ N A  ND © I o  Vhigh  AD 2 H si q Vhigh  Vlow Io  Vlow ¸ ¸ ¹ ·  AD 2 H si q Ceq N AND Io  Vhigh  N A  ND Vhigh  Vlow Io  Vlow (2) From (1),(2) C eq  2C j 0 Io Vhigh  Vlow I o  Vhigh  Io  Vlow 1 ...
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## This note was uploaded on 09/24/2009 for the course ECE 456 taught by Professor Mohammadi during the Spring '09 term at Purdue.

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