Unformatted text preview: EE456 HW1 solutions EE456 HW1 Solutions
Problem 1. To solve this problem, you can use graphical method and iteration (VOL=VOUT, VOH=VIN : Applying VOH to the input of an inverter yields VOL at the output and vice versa)
5 0.5 4.875 0.57 VOUT
0.5 4.875 0.57 4.86 VOH = 4.86V VOL = 0.57V for VIL, VIH , slope of VTC = -1 so
VIL = 2V, VIH = 3V Æ NML = VIL - VOL = 1.43V, NMH = VOH - VIH = 1.86V
The gate is regenerative since slope of VTC > 1 in midsecton. Problem 2. 'Q j Q j (Vhigh ) Q j (Vlow ) Ceq Vhigh Vlow 'VD Qj § NAND AD ¨ 2H si q ¨ NA ND © · ¸Io Vo ¸ ¹ ·1 ¸ ¸I ¹o AD 2 H si q N AND NA ND 1 Io Vo C j0 §1 NAND AD ¨ H si q ¨2 N A ND © AD NN 1 H si q A D 2 NA ND Io
N AND NA ND (1) Ceq § NAND ¨ AD 2 H si q ¨ N A ND © I o Vhigh AD 2 H si q Vhigh Vlow Io Vlow ¸ ¸
¹ · AD 2 H si q Ceq N AND Io Vhigh N A ND Vhigh Vlow Io Vlow (2) From (1),(2) C eq 2C j 0 Io Vhigh Vlow I o Vhigh Io Vlow 1 ...
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This note was uploaded on 09/24/2009 for the course ECE 456 taught by Professor Mohammadi during the Spring '09 term at Purdue.
- Spring '09
- Integrated Circuit