CHEM_115-Exam_1_Answer_Key

CHEM_115-Exam_1_Answer_Key - Name: _ Section _ CHEM 115:...

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Name: _____________________________________________________________________ Section _________ 1 CHEM 115: Sections 7-12 Exam 1 Answer Key Part I: Multiple Choice Number Answer Number Answer Number Answer 1 A 12 A 23 B 2 D 13 C 24 D 3 C 14 B 25 D 4 B 15 C 26 D 5 A 16 C 27 A 6 A 17 A 28 B 7 B 18 D 29 C 8 B 19 D 30 A 9 D 20 A 31 B 10 D 21 B 32 C 11 A 22 C 33 A Part II: Short Answer 34) (30 pts.) a) (16/30 ) Transition Emission Wavelength (nm) Letter of Band n = 6 n = 2 410 A n = 5 n = 2 434 B n = 4 n = 2 486 C n = 3 n = 2 656 D b) (5/30) When the electron of hydrogen transitions from a higher energy level to a lower one, a photon of light that is equal to the difference of the energies of the two levels is emitted. The greater the difference in energy levels, the greater the energy of the photon emitted. The 6 to 2 transition is the greatest transition of those in the table and therefore will emit the photon of the highest energy. Since the wavelength of a photon is inversely proportional to its energy, the lower the wavelength, the higher the energy of that photon. Therefore, the highest energy photon would be the one that is
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This note was uploaded on 09/24/2009 for the course CHEM 333 taught by Professor Baird during the Spring '09 term at UC Davis.

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CHEM_115-Exam_1_Answer_Key - Name: _ Section _ CHEM 115:...

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