L20-Chemical_Reactions_and_Stoichiometry

L20-Chemical_Reactions_and_Stoichiometry - Part III:...

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Part III: Chemical Reactions and Stoichiometry The Mole How Much are We Dealing With? The mole the amount ( mass ) of a substance that contains the same number of entities as there are atoms in exactly 12 g of carbon - 12 6.022 x 10 23 entities A mol e of a substance has a Fxed mass. • a method of counting chemical entities by w eighing i t The number of grams that is numerica l y the same as the atomic mass has 1 mole of that substanc e The Mol e 1 mole = 6.022 x 10 23 12 grams of 12 C 6.022 x 10 23 carbon atoms 26.98 grams of Al 6.022 x 10 23 Al atoms 207.2 grams of Pb 6.022 x 10 23 Pb atoms What About Compounds? The molecular or formula mass is equal to the sum of the individual atomic masses the same numerically as the mass of 1 mole of the compounds expressed in grams Formula Molecular/Formula Mass Molar Mass H 2 O 18.02 amu 18.02 g/mol NaOH 40.0 amu 40.0 g/mol Al(OH) 3 61.00 amu 61.00 g/mol 1 2 3 4
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What Good is this Mole - Mass Relationship? Provides a convenient conversion factor
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This note was uploaded on 09/24/2009 for the course CHEM 333 taught by Professor Baird during the Spring '09 term at UC Davis.

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L20-Chemical_Reactions_and_Stoichiometry - Part III:...

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