{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

L20-Chemical_Reactions_and_Stoichiometry

L20-Chemical_Reactions_and_Stoichiometry - Part III...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Part III: Chemical Reactions and Stoichiometry The Mole How Much are We Dealing With? The mole the amount ( mass ) of a substance that contains the same number of entities as there are atoms in exactly 12 g of carbon - 12 6.022 x 10 23 entities A mol e of a substance has a Fxed mass. • a method of counting chemical entities by w eighing i t The number of grams that is numerica l y the same as the atomic mass has 1 mole of that substanc e The Mol e 1 mole = 6.022 x 10 23 12 grams of 12 C 6.022 x 10 23 carbon atoms 26.98 grams of Al 6.022 x 10 23 Al atoms 207.2 grams of Pb 6.022 x 10 23 Pb atoms What About Compounds? The molecular or formula mass is equal to the sum of the individual atomic masses the same numerically as the mass of 1 mole of the compounds expressed in grams Formula Molecular/Formula Mass Molar Mass H 2 O 18.02 amu 18.02 g/mol NaOH 40.0 amu 40.0 g/mol Al(OH) 3 61.00 amu 61.00 g/mol 1 2 3 4
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
What Good is this Mole - Mass Relationship? Provides a convenient conversion factor
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 4

L20-Chemical_Reactions_and_Stoichiometry - Part III...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon bookmark
Ask a homework question - tutors are online