Lecture_3

# Lecture_3 - EE 311 Lecture 3 DC Solution R S = 0.1 kΩ R 1...

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EE 311 Lecture 3 Short-Circuit and Open-Circuit Time Constants Isn't there an easier way? Open-circuit time constant method: Short-circuit time constant method: Lecture 3 Page 1

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EE 311 Lecture 3 Demonstration of Time-Constant Method Sketch the network's frequency response. R S = 1 k , R P = 10 k  C S = 1 F, C P = 3 pF Lecture 3 Page 2
EE 311 Lecture 3 Another Example Plot the frequency response of this network: R S = 0. 5 kΩ, r π = 1.5 kΩ, g m = 75 mA/V, R L = 5 kΩ, C L = 10 pF | A v | dB f (Hz) Lecture 3 Page 3

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EE 311 Lecture 3 Transistor Amplifiers with Coupling and Bypass Capacitors Circuit: Model: Find the midband gain and the corner frequency, f L , and then sketch the response of the circuit: | A v | dB f (Hz) Lecture 3 Page 4

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Unformatted text preview: EE 311 Lecture 3 DC Solution R S = 0.1 kΩ, R 1 = 51.2 kΩ, R 2 = 9.6 kΩ, R C = 2 kΩ, R E = 0.4 kΩ, C C = 1 μF, V CC = 10 V, β = 100, V BE = 0.7 V I CQ , g m , r π Calculations: Lecture 3 Page 5 EE 311 Lecture 3 R i and f L Calculations R S = 0. 1 kΩ, R 1 = 51.2 kΩ, R 2 = 9.6 kΩ, R C = 2 kΩ, R E = 0.4 kΩ, C C = 1 μF, β = 100 R i Calculations: f L Calculations: Lecture 3 Page 6 EE 311 Lecture 3 Midband Gain Calculations Midband Gain Calculations: Sketch the Frequency Response: | A v | dB f (Hz) R S = 0. 1 kΩ, R 1 = 51.2 kΩ, R 2 = 9.6 kΩ, R C = 2 kΩ, R E = 0.4 kΩ, C C = 1 μF, β = 100 Lecture 3 Page 7...
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Lecture_3 - EE 311 Lecture 3 DC Solution R S = 0.1 kΩ R 1...

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