IE341HWHints[1] - 10.106: dof = 3 11.23(c): p-value =...

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IE341 Hints for HWs HW # Exercise Problem #s Due Date 1 8.7, 8.13, 8.47, 8.65, 8.78, 8.85, 8.103 Sep. 21 (Mon.) 2 9.5, 9.16, 9.38, 9.56, 9.72, 9.86, 9.95 Sep. 30 (Wed.) 3 10.7, 10.21, 10.29, 10.76, 10.83, 10.84, 10.86, 10.91, 10.106 Oct. 14 (Wed.) 4 11.3, 11.10, 11.20, 11.23, 11.38, 11.42, 11.59 Nov. 11 (Wed.) 5 11.76, 11.77, 11.82, 13.4, 13.13, 13.29 Nov. 23 (Mon.) 6 13.42, 13.53, 12.15, 14.3, 14.13, 14.25 Dec. 9 (Wed.)
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Unformatted text preview: 10.106: dof = 3 11.23(c): p-value = P(T< − 5.20) + P(T>5.20) = (2) (.00691) = .01382 If the test were (not two-tailed but) lower-tail test, then p-value = P(T< − 5.20) = .00691. 11.76: a’(X’X)-1 a = 92.776 13.13: F .± (2, ∞ ) = 5.30 < F .± (2,162) < 5.54 = F .± (2,120) 13.42: Use the formulas on p. 688. 14.3: dof = 3 14.25(c): -.21 ² .1285 (The answer on p. 894 is incorrect.)...
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This note was uploaded on 09/24/2009 for the course IE, KAIST IE+HSS taught by Professor Various. during the Spring '09 term at Korea Advanced Institute of Science and Technology.

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