# hw 3 - 1 The arc can be parameterized by t 2cos t,2sin t 0...

This preview shows pages 1–2. Sign up to view the full content.

1. The arc can be parameterized by:     2cos ,2sin 0 2 t t t t   The required integral is: 0 2 0 22 2 2sin , 2cos 2sin ,2cos 4sin 4cos 2 t t t t dt t tdt   2. Using the Divergence Theorem: 111 000 3 div 4 2 G dS dV z ydxdydz      F n F 4.             10 , 2 , 2 10 ,2 ,2 At 3, 1,2 , 50,4, 2 V r x z z y E r x z z y P E P     5. In cylindrical coordinates: Note that     ˆ ˆ 11 ˆ ˆˆ 0 4 0 0 8 0 4 8 r H r z z zz         

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 2

hw 3 - 1 The arc can be parameterized by t 2cos t,2sin t 0...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online