OFDMA_Part35 - k ! S k Update C k * = C k * + 1 For each...

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35 For each user k, set: C k = R k R max ! " " # $ $ which is the number of blocks assigned to user k. For each user k, Fnd: b k = R k ! T sym nC k which is the number of bits carried by each subcarrier for user k. SNR k = (2 b k ! 1) " which is the SNR required to meet user k's rate requirement. For each user k, Fnd: S k ' = s l l = 1 C k + 1 ! which is the power corresponding to C k + 1 blocks. ! S k = S k " S k ' Choose k * = argmax
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Unformatted text preview: k ! S k Update C k * = C k * + 1 For each user k, Fnd the total transmit power: S k = s l l = 1 C k ! where s l = SNR k ! " n 2 # h k ( l ) 2 End 1 6 5 4 7 3 2 If S k k = 1 K ! > P If S k k = 1 K ! > P If S k k = 1 K ! " P If S k k = 1 K ! " P Figure 16. Block Allocation Algorithm...
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This note was uploaded on 09/27/2009 for the course ECE 399 taught by Professor Prof during the Spring '09 term at University of Texas.

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