200904 - Chem 104A, UC, Berkeley C : 1s 2s 2 p 2 2 2 Chem...

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1 Chem 104A, UC, Berkeley 2 2 2 2 2 1 : p s s C Chem 104A, UC, Berkeley 2 2 2 2 2 1 : p s s C 0 1 2 1 0 L S 2 1 D 1 1 P 0 1 S 1 , 2 , 3 3 D 0 , 1 , 2 3 P 1 3 S ???
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2 Chem 104A, UC, Berkeley M L : total orbital-orientation quantum No. L m M l L ± ± ± = = ,.... 2 , 1 , 0 L=max(M L ) 2L + 1 possible values Chem 104A, UC, Berkeley For a given value of S, there will be 2S+1 spin states characterized by M S. M S = m s =0, ± 1, ± 2,…. ± S for even # unpaired electrons = ± 1/2, ± 3/2, ± 5/2,…. ± S for odd # of electrons. S=max (M S )
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3 Chem 104A, UC, Berkeley 2 2 2 2 2 1 : p s s C S=0 M s =0 S=1 M s =1 M s =-1 M s =0 S=0 M s=0 Chem 104A, UC, Berkeley N = (2 y )! x !(2 y x )! In general, the total No. of ways N that x electrons can be placed into y orbitals of equivalent energy with either spins is given by 2 2 2 2 2 1 : p s s C 15 ! 4 ! 2 ! 6 = microstates 4!=Factorial 4=1x2x3x4
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4 Chem 104A, UC, Berkeley Step I: Sum all m s and m l for each microstates, Determine M S, M L for each M S = m s M L = m l Chem 104A, UC, Berkeley l m +1 0 -1 s M L M 0 0 0 0 0 0 0 0 0 1 -1 1 -1 1 -1 -2 0 2 -1 -1 0 0 1 1 -1 -1 0 0 1 1
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This note was uploaded on 09/28/2009 for the course CHEM 104a taught by Professor Staff during the Spring '08 term at University of California, Berkeley.

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200904 - Chem 104A, UC, Berkeley C : 1s 2s 2 p 2 2 2 Chem...

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