Unit 16 - Tuned Circuits and RLC Networks

Unit 16 - Tuned Circuits and RLC Networks - Ch15.3:...

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Ch15.3: Capacitance in AC Circuits Series RC Circuits: Given a series circuit containing a 100 resistance and a 3.3 μ F capacitance with an applied voltage of 24 V at 500 Hz, compute the capacitive reactance, impedance, total current, voltage drops, phase angle, apparent power, true power, power factor, and draw the phasor diagram. Solution: τ = R x C = (100)(3.3)(10 -6 ) = 330 μ S X C = 1/(2 π fC) = 1/[(2)( π )(500)(3.3)(10 -6 )] = 96.51 Z = (R 2 + X C 2 ) = 100 2 + 96.51 2 ) = 138.98 I T = E S /Z = 24/138.98 = 172.69 mA E R = I R x R = (0.17269)(100) = 17.27 V E C = I L x X C = (0.17269)(96.51) = 16.67 V θ = cos-1(R/Z) = cos-1(100/138.98) = cos-1(.7195) = 43.98° P a = E S x I T = (24)(0.17269) = 4.14 VA P t = E S x I T x cos θ = (24)(0.17269)(.7195) = 2.98 W PF = P t /P a = 2.98/4.14 = .7195 = cos θ `
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Ch15.3: Capacitance in AC Circuits Draw the phasor diagram (X c /R) X L R = 33.3°
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Ch15.3: Capacitance in AC Circuits Parallel RC Circuits: Given a circuit containing a 100 resistance in parallel with a 3.3 μ F capacitance with an applied voltage of 24 V at 500 Hz, compute the capacitive reactance, branch currents, total current, impedance, phase angle between the currents, apparent power, true power, power factor, and draw the phasor diagram. Solution: τ = R x C = (100)(3.3)(10 -6 ) = 330 μ S X C = 1/(2 π fC) = 1/[(2)(3.14)(500)(3.3)(10 -6 )] = 96.51 I R = E R /R = 24/100 = 24.0 mA I C = E C /X C = 24/96.51 = 24.87 mA I T = (I R 2 + I C 2 ) = (24.0 2 + 24.87 2 ) = 34.56 mA Z = E S / I T = 24/0.03456 = 693.64 θ = tan -1 (I C /I R ) = tan -1 (24.87/24) = tan -1 (1.03625) = 46.10° P a = I T x E S = (0.03456)(24) = .829 VA P t = I T x E S x cos θ = (0.03456)(24)(.6934) = .575 W PF = P t/ P a = .575/.829 = .6936 = cos θ Draw the phasor diagram (I C /I R )
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Ch15.3: Capacitance in AC Circuits Draw the phasor diagram (I C /I R ) 24.87 mA I T = 198.46 mA I C θ = 46.10° I R 24.0 A
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7 17 29-Oct Mon AC Motors Primer Ch13 AC/DC Generators/Oscope SA 13-1, 13-2 18 31-Oct Wed Ch 9-13 Summary Ch9-13 (SA 10-3, 11-3, 11-5, 12-2) Summary Handout 19 2-Nov Fri Exam #3 - 8 20 5-Nov Mon Inductance & RL Circuits Ch14 RLC Circuits SA 14-1 21 7-Nov Wed Inductance & RL Circuits Ch14 (SA 14-2, 15-2) 22 9-Nov Fri Capacitance and RC Circuits Ch15 SA 15-1 9 12-Nov Mon Veteran's Day: No School RLC Circuits 23 14-Nov Wed Tuned RLC Circuits Ch16 (SA 16-2, 16-3) SA 16-1 24 16-Nov Fri Diodes & Power Supplies Ch17 SA 17-1 10 25 19-Nov Mon Diodes & Power Supplies Ch17 NO LAB 21-Nov Wed Thanksgiving Holiday 23-Nov Fri Thanksgiving Holida y 11 26 26-Nov Mon Ch 14-17 Summary Ch14-17 Diodes and Power Supplies Summary Handout 27 28-Nov Wed Exam #4 - (SA 17-3, 17-4, 17-6, 17-7) 28 30-Nov Fri Final Exam Review 5-Dec Wed Final Exam 0710-1000)
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Electronic Systems Chapter 16: Tuned Circuits and RCL Networks
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RCL Networks RCL Networks
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Ch16: Tuned Circuits and RCL Networks Ch16: Tuned Circuits and RCL Networks Today’s Stuff . . . - Resonance - Series RCL Resonant Circuits - Parallel RCL Resonant Circuits - Filters
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Why an IT graduate should know this . . . - Learned people (and almost all technical types) know how/where to find it in a book and (then) can understand it . . . . - Inductance, capacitance, and resistance (either separately or in combination) represent the reasonswhy a wide variety of electrical and electronic circuits behave as they do . . . .
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Unit 16 - Tuned Circuits and RLC Networks - Ch15.3:...

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