hmk 3 olutions

# hmk 3 olutions - 9 = 4.2 nm p = k = 1.05459 × 10 − 34...

This preview shows page 1. Sign up to view the full content.

EEE 352—Fall 2009 Homework 3 2.17 Consider the wave function for -1 x 1. Determine A so that 2.20 An electron in free space is described by a plane wave given by ψ ( x ) = Ae i ( kx ω t ) where k = 1.5 × 10 9 /m and = 1.5 10 13 rad/s. (a) Determine the phase velocity of the plane wave. (b) Calculate the wavelength, momentum, and kinetic energy (in eV) of the electron. (a) v phase = k = 1.5 × 10 13 1.5 × 10 9 = 10 4 m / s (b) λ = 2 π k = 2 1.5 × 10
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 9 = 4.2 nm p = k = 1.05459 × 10 − 34 ⋅ 1.5 × 10 9 = 1.58 × 10 − 25 kg − m / s T = p 2 2 m = (1.58 × 10 − 25 ) 2 2 ⋅ 9.1 × 10 − 31 = 1.375 × 10 − 20 J = 86 meV . 2.22 An electron is bound in a one-dimensional infinite potential well with a width of 100 Å. Determine the energy levels for n = 1,2,3. From (2.37), we have Hence...
View Full Document

## This note was uploaded on 09/28/2009 for the course EEE 352/333 taught by Professor Allee during the Fall '09 term at ASU.

Ask a homework question - tutors are online