Exam3Solutions - CePrNdPmSmEuGdTbDyHoErTmYbLu...

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Unformatted text preview: CePrNdPmSmEuGdTbDyHoErTmYbLu ThPaUNpPuAmCmBkCfEsFmMdNoLr HHe LiBeBCNOFNe NaMgAlSiPSClAr KCaScTiVCrMnFeCoNiCuZnGaGeAsSeBrKr RbSrYZrNbMoTcRuRhPdAgCdInSnSbTeIXe CsBaLaHfTaWReOsIrPtAuHgTlPbBiPoAtRn FrRaAcRfDbSgBhHsMt 12 345678910 1112131415161718 192021222324252627282930313233343536 373839404142434445464748495051525354 555657727374757677787980818283848586 878889104105106107108109 5859606162636465666768697071 90919293949596979899100101102103 1.00794.0026 6.9419.012210.81112.01114.006715.999418.998420.1797 22.989824.305026.981528.085530.973832.06635.452739.948 39.098340.07844.955947.8850.941551.996154.938055.84758.933258.6963.54665.3969.72372.6174.921678.9679.90483.80 85.467887.6288.905991.22492.906495.94(98)101.07102.9055106.42107.8682112.411114.82118.710121.75127.60126.9045131.39 132.9054137.327138.9055178.49180.9479183.85186.207190.2192.22195.08196.9665200.59204.3833207.2208.9804(209)(210)(222) (223)(226)(227)(261)(262)(263)(262)(265)(266) 140.115140.9076144.24(145)150.36151.965157.25158.9253162.50164.9303167.26168.9342173.04174.967 232.0381231.0359238.0289(237)(244)(243)(247)(247)(251)(252)(257)(258)(259)(260) 1A8A 2A3A4A5A6A7A 3B4B5B6B7B8B1B2B 118 21314151617 3456789101112 Periodic Table of the Elements Johnson, Chelsea Exam 3 Due: Apr 4 2007, 10:00 am Inst: Walker 2 This print-out should have 17 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. Read all of the options before choosing one. There may be cases in which more than one response appears to be true. PICK THE RE- SPONSE THAT BEST answers the question asked. NOTE: Some questions are worth more points than others, as indicated at the top of each question. .......Barium chloride is SOLUBLE........ 001 (part 1 of 1) 18 points A 130 mL portion of 0 . 4 M acetic acid is be- ing titrated with 0 . 4 M NaOH solution. What is the pH of the solution after 100 mL of the NaOH solution has been added? The ioniza- tion constant of acetic acid is 1 . 8 10- 5 . 1. pH = 4 . 93 2. pH = 5 . 27 correct 3. pH = 5 . 49 4. pH = 4 . 22 5. pH = 4 . 54 Explanation: V CH 3 COOH = 130 mL [CH 3 COOH] = 0 . 4 M V NaOH = 100 mL [NaOH] = 0 . 4 M K a = 1 . 8 10- 5 For CH 3 COOH, (0 . 4 M)(0 . 13 L) = 0 . 052 mol For NaOH, (0 . 4 M)(0 . 1 L) = 0 . 04 mol CH 3 COOH + NaOH NaCH 3 COO + H 2 O . 052 mol . 04 mol 0 mol- . 04 mol- . 04 mol +0 . 04 mol . 012 mol 0 mol...
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Exam3Solutions - CePrNdPmSmEuGdTbDyHoErTmYbLu...

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