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Exam4Sol

# Exam4Sol - NOTE If the potential is NOT given in the...

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NOTE: If the potential is NOT given in the problem on the exam, then please use this table. When the potential is given in the problem, then use what is given. Standand Potentials at 25 C half-reactions volts F 2 + 2 e - -→ 2 F - +2.87 V Ce 4+ + e - -→ Ce 3+ +1.61 V MnO - 4 + 8 H + + 5 e - -→ Mn 2+ + 4 H 2 O +1.51 V Cr 2 O 2 - 7 + 14 H + + 6 e - -→ 2 Cr 3+ + 7 H 2 O +1.33 V Cl 2 + 2 e - -→ 2 Cl - +1.36 V O 2 + 4 H + + 4 e - -→ 2 H 2 O +1.23 V Ag + + e - -→ Ag +0.80 V Fe 3+ + e - -→ Fe 2+ +0.77 V Cu 2+ + 2 e - -→ Cu +0.34 V AgCl + e - -→ Ag + + Cl - +0.22 V 2 H + + 2 e - -→ H 2 0.000 V Fe 3+ + 3 e - -→ Fe -0.04 V Fe 2+ + 2 e - -→ Fe -0.44 V Zn 2+ + 2 e - -→ Zn -0.76 V Mn 2+ + 2 e - -→ Mn -1.18 V Ti 2+ + 2 e - -→ Ti -1.63 V Al 3+ + 3 e - -→ Al -1.66 V Li + + e - -→ Li -3.05 V For Rate Problems on the Exam: You should assume that the reaction coefficient is ONE (1) unless told (or shown) otherwise.

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Moore, Robert – Exam 4 – Due: May 1 2007, noon – Inst: McCord 2 This print-out should have 23 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points A mechanism for the decomposition of ozone (2 O 3 3 O 2 ) is O 3 O 2 + O O + O 3 O 2 + O 2 What is the molecularity for the first and second elementary reactions? 1. 2 and 1 2. 1 and 2 correct 3. 1 and 1 4. 2 and 2 5. None of these Explanation: 002 (part 1 of 1) 10 points How many liters of F 2 (g) at STP could be pro- duced by the electrolysis of molten NaF with a constant 2.75 amp current for 160 minutes? 1. 0.102 L 2. 0.0511 L 3. 0.326 L 4. 3.06 L correct 5. 6.13 L 6. 0.163 L Explanation: 003 (part 1 of 1) 10 points For the reaction 2 NO(g) + 2 H 2 (g) N 2 (g) + 2 H 2 O(g) the following data were collected. [NO(g)] [H 2 (g)] Rate, M/s 0.10 0.10 0.0050 0.10 0.20 0.010 0.10 0.30 0.015 0.20 0.10 0.020 0.20 0.20 0.040 What is the rate law for this reaction? 1. rate = k [H 2 ] [NO] 2. rate = k [H 2 ] [NO] 2 correct 3. rate = k [H 2 ] [NO] 2 4. rate = k [H 2 ] [NO] 5. None of these 6. rate = k [H 2 ] 2 [NO] Explanation: 004 (part 1 of 1) 10 points Consider the multistep reaction that has the overall reaction 2 A + B 2 C + D . What would be the observed rate expression? Mechanism: 2 A C + I (slow) I + B C + D (fast) 1. Rate = k [A] 2 correct 2. Rate = k [A] 3. Rate = k [A] 2 [B] 4. Rate = k [I] [B] 5. Rate = k [A] [I] [B]
Moore, Robert – Exam 4 – Due: May 1 2007, noon – Inst: McCord 3 Explanation: The first step is the slowest step (the rate determining step), so the rate law can be written based on the stoichiometry of the re- actant.

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