H08- Acids-Bases 2-solutions

H08- Acids-Bases 2-solutions - patteson (dmp786) H08:...

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1 This print-out should have 17 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 10.0 points The term “ K a For the ammonium ion” de- scribes the equilibrium constant For which oF the Following reactions? 1. NH + 4 + H 2 O NH 3 + H 3 O + correct 2. NH + 4 + OH NH 3 + H 2 O 3. NH 4 Cl(solid) + H 2 O NH + 4 + Cl 4. NH 3 + H 2 O NH 4 + + OH 5. The term is misleading, because the am- monium ion is not an acid. 6. NH 3 + H 3 O + NH + 4 + H 2 O Explanation: 002 10.0 points Hydroxylamine is a weak molecular base with K b = 6 . 6 × 10 9 . What is the pH oF a 0.0500 M solution oF hydroxylamine? 1. pH = 3.63 2. pH = 7.12 3. pH = 9.26 correct 4. pH = 8.93 5. pH = 4.74 6. pH = 10.37 7. pH = 9.48 Explanation: Hydroxylamine is a weak base, so use the equation to calculate weak base [OH ] con- centration (note that this is the approximate equation. Why? Because K b is very small and the concentration is reasonable) : [OH ] = r K b C b = R (6 . 6 × 10 9 ) (0 . 0500) = 1 . 82 × 10 5 AFter fnding [OH ], you can fnd pH using either method below: A) pOH = log ( 1 . 82 × 10 5 ) = 4 . 74 pH = 14 4 . 74 = 9 . 26 or B) [H + ] = K w [OH ] = 1 . 0 × 10 14 1 . 82 × 10 5 = 5 . 52 × 10 10 pH = log ( 5 . 52 × 10 10 ) = 9 . 26 003 (part 1 oF 2) 10.0 points Calculate the pH oF the solute in an aqueous solution oF 0 . 405 M C 5 H 5 N(aq) (pyridine) iF the K b is 1 . 8 × 10 9 . Correct answer: 9 . 43136. Explanation: C pyridine = 0 . 405 M K b = 1 . 8 × 10 9 C 5 H 5 N + H 2 O C 6 H 5 NH + + OH 0 . 405 0 0 x + x + x 0 . 405 x x x K b = [C 6 H 5 NH + ][OH ] [C 5 H 5 N] 1 . 8 × 10 9 = x 2 0 . 405 x x 2 0 . 405 x = [OH ] = R 0 . 405(1 . 8 × 10 9 ) = 2 . 7 × 10 5 mol / L . The pOH is
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This note was uploaded on 09/28/2009 for the course GE 206E taught by Professor staff during the Spring '09 term at University of Texas at Austin.

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H08- Acids-Bases 2-solutions - patteson (dmp786) H08:...

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