This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: C C C = = =157053690 ) 3963 ( 100 ) 3963 ( 100 2 2 c. Use the value of C you found in the previous question to determine how much the object would weigh in i. Death Valley (282 feet below sea level) 003 . 100 ) 946 . 3962 ( 1570536900 2 2 = = =w w Cr w ii. The top of Mt McKinley (20,320 feet above sea level) 806 . 98 = w 2. The equation h D 2 . 1 = gives the distance, D, in miles that a person can see to the horizon from a height, h, in feet. a. Solve this equation for h. MAT 117 h D h D h D h D = = = = 44 . 1 2 . 1 2 . 1 2 . 1 2 2 b. Long’s Peak in the Rocky Mountain National Park, is 14,255 feet in elevation. How far can you see to the horizon from the top of Long’s Peak? Can you see Cheyenne, Wyoming (about 89 miles away)? Explain your answer. 27 . 143 ) 394 . 119 ( 2 . 1 14255 2 . 1 2 . 1 = = = = D D D h D If you can see 143.27 miles you can easily see Cheyenne Wyoming at only 89 miles away. MAT 117...
View
Full
Document
This note was uploaded on 09/29/2009 for the course MATH 117 MATH 117 taught by Professor Benhadj during the Spring '09 term at University of Phoenix.
 Spring '09
 BENHADJ

Click to edit the document details