Soln_Fall2008_HW9

# Soln_Fall2008_HW9 - SOLUTIONS HW-9 1 The air conditioner in...

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SOLUTIONS HW-9 1. The air conditioner in a car uses R-134a and the compressor power input is 2 kW, bringing the R-134a from 165kPa to 1200kPa by compression. The cool space is a heat exchanger that cools 35°C atmospheric air from the outside down to 15°C and blows it into the car. What is the mass flow rate of the refrigerant and what is the low temperature heat transfer rate? Also, find the mass flow rate of air at 15°C. P 1 = P 4 = 165 kPa P 2 = P 3 = 1200kPa. The fluid that enters the turbine is saturated vapor. Hence s1 = sg and h 1 = h g s 1 = s 2 = 1.7354 kJ/kgK We know P and s at state 2. Hence we get h 2 = 430.7 kJ/kg (interpolate.) The fluid that leaves the condenser is saturated liquid. Hence h 3 = h f = 266 kJ/kg (Interpolation) Isenthalpic throttling. Hence h 4 = h 3 Hence Wc = m (h 2 - h 1 ) So, mass flow rate m = 2/ (430.7-389.2) = 0.048 kg/s Q L = m (h 1 – h 4 ) = 0.048(389.2-266.05) = 5.94 kW But Q L is also mair*Cp*(Tout – Tin) Hence mass of air = 5.94/(1.004*20) = 0.2949 kg/s

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2. In an actual refrigeration cycle using R-134a as the working fluid, the flow rate is 0.02kg/s. Vapor enters the compressor at 100kPa and -10°C and leaves at 1MPa
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## This note was uploaded on 09/29/2009 for the course ME 530.230 taught by Professor Katz during the Spring '09 term at Johns Hopkins.

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Soln_Fall2008_HW9 - SOLUTIONS HW-9 1 The air conditioner in...

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