sol6S09 - PSTAT 120C: Assignment # 6 Solutions June 1, 2009...

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Assignment # 6 Solutions June 1, 2009 1. To form a new table to test marginal independence, we put the minority and gender categories together Right Track Wrong Track Don’t Know Total White (Women) 122 200 36 358 Minority (Women) 93 36 10 139 White (Men) 117 92 34 243 Minority (Men) 89 34 10 133 Total 421 362 90 873 The expected values in each cell are Right Track Wrong Track Don’t Know Total White (Women) 172.3 148.4 36.8 358 Minority (Women) 66.9 57.6 14.3 139 White (Men) 117.2 100.9 25.0 243 Minority (Men) 64.2 55.3 13.7 133 Total 421 362 90 873 The chi-squared test statistic is therefore, X 2 = 14 . 96 + 18 . 10 + 0 . 03+ + 10 . 19 + 8 . 32 + 1 . 25+ + 0 . 001 + 0 . 79 + 3 . 47+ + 9 . 79 + 7 . 99 + 1 . 20 = 76 . 09 which is significant when compared to a χ 2 0 . 05 , 6 = 12 . 59. Therefore, there is evidence that political opinion is not independent of these demographic factors. 2. (a) The expected values are Want stricter laws Don’t want stricter laws 18-49 188 328 516 E 206 310 ( E - O ) 2 /E 1.55 1.03 50+ 217 282 499 E 199 300 ( E - O ) 2 /E 1.61 1.07 405 610 1015 So that the χ 2 statistic is 5.26 which is not significant at the α = 0 . 01 level because it is less than the critical value 6.63. 1
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sol6S09 - PSTAT 120C: Assignment # 6 Solutions June 1, 2009...

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