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ss_1 - Problem set 1 Callister 2.7 The electron...

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Problem set 1 Callister 2.7 The electron configurations for the ions are determined using Table 2.2 (and Figure 2.6) 6 2 2 5 2 2 1 : p s s P + 6 2 2 5 2 2 1 : p s s P + 3s 6 2 3 p 10 6 2 10 6 2 6 2 2 4 4 4 4 3 3 3 2 2 1 : d p s d p s p s s Sn + 6 2 10 6 2 6 2 2 2 4 4 3 3 3 2 2 1 : p s d p s p s s Se 6 2 10 6 2 10 6 2 6 2 2 5 5 4 4 4 3 3 3 2 2 1 : p s d p s d p s p s s I 8 6 2 6 2 2 2 3 3 3 2 2 1 : d p s p s s Ni + Core 2.12 (a) The atomic number of the element sodium (Na) is 11. Write the electron configuration using the spdf notation. (b) Based on its electron configuration, briefly explain why Na has a low electronegativity (0.9). (c) Sketch a planetary model of a sodium atom labeling each electron orbital with it spdf designation. (a) 1 6 2 3 2 2 1 s p s s (b) Losing an electron to fill the n =2 orbital (2s + 2p) is more favorable than gaining an electron to fill 3s. Since electronegativity is a measure of how strongly an atom attracts an electron, Na thus has a low electronegativity.
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