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# Chapter%209%20guided%20review%20answers - have the same...

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Chapter 9 Guided Review Answers 1. Around each charge the equipotentials are circular. As you move farther from the charges the effect of the other charges becomes more important. As you move farther away and get far from the outside of the square, the equipotentials become circular as though the charges are combined together in the same space. 2. a) The force is 3.6 x 10 -4 N in all positions since the field is constant. b) W A to B =0, W A to C =-1.1 mJ, W A to D =-1.1 mJ; c) the work done is equal to the change in the potential energy, so the answers are the same as in (b); d) V B =0; V C =-36 V; V D =-36 V 3. W C to A =1.1 mJ, W C to B =1.1 mJ, W C to D =0 4. a) an electron would feel a force in the opposite direction to the field because it has a negative charge. Therefore it would move away from C toward A along a straight line. b) 2.4 μ s 5. 5.8 x 10 -20 J 6. 1.3x 10 5 V 7. Yes, the sum of the charges must be equal to zero in this case since their ditaces to the center are all the same. So, some must be negative, some positive and they cannot all
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Unformatted text preview: have the same magnitude. 8. a) the proton will slow down as it approaches the alpha particle, stop, then turn around and go back the other way as it is being decelerated by the repulsive force between it and the positively charged alpha particle. b) see example 8 in the text; c) 1.4 nm 9) 1.7v escape 10) K electron = K protron =50 eV or 8.0 x 10-18 J; K alpha =1.6 x 10-17 J; v electron =4.2 x 10 6 m/s, v protron =9.8 x 10 4 m/s, v alpha =6.9 x 10 4 m/s 11) 0.45 J 12) a) 30v, b) 1.5 A, c) CW, d) CCW, e) 45 Watts 13) a) 4.8 Ω , b) I 8 =3 A, I 12 =2 A, c) 24 V, d) 120 W, e) R 8 =48 W, I 12 =48 W 14) a) parallel, b) 2mA, c) 0.24 J, d) 30 k Ω , e) 4 mA, f) 0.48 J, g) 7.5 x 10 6 s or 86.8 days, or about 3 months. 15) 180 m. This is a lot of wire, which is why we consider electric wires to have almost no resistance and don’t include them when we calculate the equivalent resistance in a circuit....
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