summer hmwk 4

# summer hmwk 4 - 1 ELECTRIC CIRCUITS HW4 Solutions Chapter...

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1 ELECTRIC CIRCUITS HW4 Solutions Chapter 19 31. REASONING The electric potential V at a distance r from a point charge q is V = kq / r (Equation 19.6). The potential is the same at all points on a spherical surface whose distance from the charge is r = kq / V . We will use this relation to find the distance between the two equipotential surfaces. SOLUTION The radial distance r 75 from the charge to the 75.0-V equipotential surface is r 75 = kq / V 75 , and the distance to the 190-V equipotential surface is r 190 = kq / V 190 . The distance between these two surfaces is ( 29 75 190 75 190 75 190 2 9 8 2 1 1 N m 1 1 8.99 10 1.50 10 C 1.1 m 75.0 V 190 V C kq kq r r kq V V V V - - = - = - = × + × - = Chapter 20 1. REASONING The current I is defined in Equation 20.1 as the amount of charge q per unit of time t that flows in a wire. Therefore, the amount of charge is the product of the current and the time interval. The number of electrons is equal to the charge that flows

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summer hmwk 4 - 1 ELECTRIC CIRCUITS HW4 Solutions Chapter...

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