HW9%20solutions

HW9%20solutions - Homework 9 solutions Physics 204, morning...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Homework 9 solutions Physics 204, morning summer 2008 Chapter 22 Problems 40,59 Chapter 24 Problem 1 Chapter 25 Problems 5,2 40. REASONING The length of the wire is the number N of turns times the length per turn. Since each turn is a square that is a length L on a side, the length per turn is 4 L , and the total length is N (4 L ). Since the area of a square is A = L 2 , the length of a side of the square can be obtained as LA = , so that the total length is () 4 NA 0 NA . The area can be found from the peak emf, which is B ξ ω = , according to Equation 22.4. Solving this expression for A and substituting the result into the expression for the total length gives 00 Total length 4 4 4 N N NB B ⎜⎟ ⎝⎠ ⎛⎞ == = 0 (1) Although we are not given the peak emf , we know that it is related to the rms emf, which is known: 0r m s 2 = (Equation 20.13). We are also not given the angular speed ω , but we know that it is related to the frequency f in hertz according to 2 f π = (Equation 10.6).
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 10/04/2009 for the course PHYS 750:204 taught by Professor Rollino during the Spring '09 term at Rutgers.

Page1 / 3

HW9%20solutions - Homework 9 solutions Physics 204, morning...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online