HW10%20solutions

HW10%20solutions - Homework 10 solutions Physics 204,...

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Homework 10 solutions Physics 204, morning summer 2008 Chapter 25 Problems 20,33,19 Chapter 26 Problems 11,24 20. REASONING Since the focal length f and the object distance d o are known, we will use the mirror equation to determine the image distance d i . Then, knowing the image distance as well as the object distance, we will use the magnification equation to find the magnification m . SOLUTION a. According to the mirror equation (Equation 25.3), we have () i io o 111 1 1 or 4.3 m 11 1 1 7.0 m 11 m d df d fd =− = = = −− The image distance is negative because the image is a virtual image behind the mirror. b. According to the magnification equation (Equation 25.4), the magnification is ( ) i o 4.3 m 0.39 11 m d m d = 33. REASONING AND SOLUTION a. The focal length is found from 1 1 27 1 65 46 d f =+= + =+ oi cm cm so cm b. The magnification is m d d = = = i o cm 27 cm 65 24 bg . 19. REASONING a. We are dealing with a concave mirror whose radius of curvature is 56.0 cm. Thus, the focal length of the mirror is 1 2 28.0 cm fR == (Equation 25.1) The object distance is d o = 31.0 cm. With known values for
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This note was uploaded on 10/04/2009 for the course PHYS 750:204 taught by Professor Rollino during the Spring '09 term at Rutgers.

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HW10%20solutions - Homework 10 solutions Physics 204,...

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