HW11%20solutions

HW11%20solutions - Homework 11 solutions Physics 204...

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Homework 11 solutions Physics 204, morning summer 2008 Chapter 26 Problems 51,44,67 Chapter 27 Problems 2,52 51. REASONING We can use the magnification equation (Equation 26.7) to determine the image height h i . This equation is ii io oo o or hd d hh d ⎛⎞ =− = ⎝⎠ i (26.7) We are given the object height h o and the object distance d o . Thus, we need to begin by finding the image distance d i , for which we use the thin-lens equation (Equation 26.6): i oi i o o o 111 or or df f d d ddf d f d += = = (26.6) Substituting this result into Equation 26.7 gives o i o o o 1 fd d f h h dd d f f ⎛⎞⎛⎞ ⎞⎛ = ⎜⎟⎜⎟ ⎟⎜ −− ⎝⎠⎝⎠ ⎠⎝ o d (1) SOLUTION a. Using Equation (1), we find that the image height for the 35.0-mm lens is () 3 3 o 35.0 10 m 1.60 m 0.00625 m 35.0 10 m 9.00 m f fd ⎡⎤ × ⎢⎥ == = ⎜⎟ ×− ⎣⎦ b. Using Equation (1), we find that the image height for the 150.0-mm lens is 3 3 o 150.0 10 m 1.60 m 0.0271 m 150.0 10 m 9.00 m f × = Both heights are negative because the images are inverted with respect to the object.
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This note was uploaded on 10/04/2009 for the course PHYS 750:204 taught by Professor Rollino during the Spring '09 term at Rutgers.

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HW11%20solutions - Homework 11 solutions Physics 204...

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