Recitation ClassWork 9 solutions
Physics 204, morning summer 2008
Chapter 26
Concepts & Calculations #123
Chapter 27
Conceptual Questions #5
Concepts & Calculations #60
123.
CONCEPT QUESTION
In part
a
of the drawing, the object lies inside the focal point of the converging
(#1) lens.
According to Figure 26.28, such an object produces a virtual image that lies to the left of the lens.
This image act as the object for the diverging (#2) lens.
Since a diverging lens always produces a virtual image
that lies to the left of the lens, the final image lies to the left of the diverging lens.
In part (b), the diverging (#1)
lens produces a virtual image that lies to the left of the lens.
This image act as the object for the converging
(#2) lens.
Since the object lies outside the focal point of the converging lens,
the converging lens produces a
real image that lies to the right of the lens (see Figure 26.26).
Thus, the final image lies to the right of the
converging lens.
SOLUTION
a.
The focal length of lens #1 is
f
1
= 15.00 cm, and the object distance is
d
o1
= 10.0 cm.
The image distance
d
i1
produced by the first lens can be obtained from the thinlens equation, Equation 26.6:
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 Spring '09
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