HW 3 Solutions

# HW 3 Solutions - kim(jkk547 – HW03 – markert –(58840...

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Unformatted text preview: kim (jkk547) – HW03 – markert – (58840) 1 This print-out should have 21 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points A superhero flies 258 m from the top of a tall building at an angle of 25 ◦ below the horizontal. Draw the vectors to scale on a graph to determine the answer. a) What is the horizontal component of the superhero’s displacement? Correct answer: 233 . 827 m. Explanation: 233 . 827 m- 109 . 036m 258 m Scale: 100 m- 2 5 ◦ Basic Concept: Δ x = d (cos θ ) Given: d = 258 m θ =- 25 ◦ Solution: Δ x = (258 m)[cos(- 25 ◦ )] = 233 . 827 m . 002 (part 2 of 2) 10.0 points b) What is the vertical component of the su- perhero’s displacement? Correct answer:- 109 . 036 m. Explanation: Basic Concept: Δ y = d (sin θ ) Solution: Δ y = (258 m)[sin(- 25 ◦ )] =- 109 . 036 m . 003 10.0 points Consider the vectors vector A and vector B . vector A vector B Which sketch shows the vector vector A- vector B to the same scale? 1. 2. correct 3. 4. 5. 6. 7. kim (jkk547) – HW03 – markert – (58840) 2 8. Explanation: vector A- vector B vector A- vector B 004 10.0 points A car travels 2 . 33 km in the x-direction, then turns left 80 . 3 ◦ to the original direction and travels an additional distance of 2 . 52 km. Calculate the x component of the car’s net displacement. Correct answer: 2 . 75459 km. Explanation: The x component of the car’s net displace- ment is simply (2 . 33 km)(cos 0 ◦ )+(2 . 52 km)(cos 80 . 3 ◦ ) = 2 . 75459 km . 005 (part 1 of 2) 10.0 points A skier squats low and races down a(n) 17 ◦ ski slope. During a 7 s interval, the skier accelerates at 3 . 3 m / s 2 . a) What is the horizontal component of the skier’s acceleration (perpendicular to the direction of free fall)? Correct answer: 3 . 15581 m / s 2 . Explanation: a y a x 3 . 3 m / s 2- 17 ◦ Note: Figure is not drawn to scale. Basic Concept: a x = a (cos θ ) Given: θ =- 17 ◦ a = 3 . 3 m / s 2 Solution: a x = (3 . 3 m / s 2 )[cos(- 17 ◦ )] = 3 . 15581 m / s 2 006 (part 2 of 2) 10.0 points b) What is the vertical component of the skier’s acceleration? Correct answer:- . 964827 m / s 2 . Explanation: Basic Concept: a y = a (sin θ ) Solution: a y = (3 . 3 m / s 2 )[sin(- 17 ◦ )] =- . 964827 m / s 2 007 (part 1 of 2) 10.0 points A descent vehicle landing on the moon has a vertical velocity toward the surface of the moon of 37 . 2 m / s. At the same time, it has a horizontal velocity of 55...
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HW 3 Solutions - kim(jkk547 – HW03 – markert –(58840...

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