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Unformatted text preview: = 3 = 1800 nm . 3. Now, wed like to gure out what the pattern looks like when we ll the space between the slabs with water. This time, the interfaces are n = 1 . 5 to 1.33 and n = 1 . 33 to n = 1 . 2 (so neither ray picks up a phase shift). Thus, the far left of the pattern will be bright. Now, the thickness t hasnt changed, so we know that m water = 2 t , where m is the number of times the pattern cycles all the way back to bright, and water = /n water . Well say n water = 4 / 3 for ease of calculation. Thus we nd m = 2 (1800 nm) (4 / 3) / (600 nm) = 8 . So the pattern in water starts bright, and cycles back to bright 8 times. 1...
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 Spring '08
 LIN
 Quantum Physics

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