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# HW1Sol - Solutions to WebAssign HW#1 Giancoli Ch 31 3 4 10...

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Unformatted text preview: Solutions to WebAssign HW #1 - Giancoli Ch. 31- 3, 4, 10, 14, 28, 49, 56; (due 1/28) 3. The current in the wires must also be the displacement current in the capacitor. Use the displacement current to find the rate at which the electric field is changing. ( ) ( ) ( ) 15 D 2 12 2 2 2.8A V 1.2 10 m s 8.85 10 C N m 0.0160m D dE dE I A dt dt A I = = = = 4. The current in the wires is the rate at which charge is accumulating on the plates and also is the displacement current in the capacitor. Because the location in question is outside the capacitor, use the expression for the magnetic field of a long wire. ( ) ( ) ( ) 7 3 8 10 T m A 2 38.0 10 A 2 7.60 10 T 2 4 . 1 m I I B R R = = = = After the capacitor is fully charged, all currents will be zero, so the magnetic field will be zero. 10. The frequency of the two fields must be the same: 80.0kHz . The rms strength of the electric field can be found from Eq. 31-11 with can be found from Eq....
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HW1Sol - Solutions to WebAssign HW#1 Giancoli Ch 31 3 4 10...

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