# HW2Sol - Solutions to WebAssign HW#2 Giancoli Ch 32 4 13 25...

This preview shows pages 1–2. Sign up to view the full content.

Solutions to WebAssign HW #2 - Giancoli Ch. 32- 4, 13, 25, 41, 45, 53, 58, 59, 60, 64; (due 2/4) 4. The angle of incidence is the angle of reflection. See the diagram for the appropriate lengths. () tan 1.64m 0.38m (0.38m) 0.69m 2.30m Hh h x x x θ == =→ = l 13. The ball is a convex mirror with a focal length ( ) 11 22 4.6cm 2.3cm. fr = Use Eq. 32- 3 to locate the image. ( )( ) o i oi o 25.0cm 2.3cm 111 2.106cm 2.1cm 25.0cm 2.3cm df d dd f += = = = −− The image is 2.1 cm behind the surface of the ball, virtual, and upright. Note that the magnification is ( ) i o 2.106cm 0.084. 25.0cm d m d =− = =+ ( a ) To produce a smaller image located behind the surface of the mirror requires a ( b ) Find the image distance from the magnification. ( )( ) ii o i i oo o 26cm 3.5cm 20.2cm 20cm 4.5cm hd d h md h = = = (2 sig. fig.) As expected, i 0. d < The image is located ( c ) Find the focal length from Eq. 32.3. ( )( ) ( ) o i 26cm 20.2cm 1 90.55cm 91cm 20.2cm f ddf d d →= = = ++ ( d ) The radius of curvature is twice the focal length.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 10/05/2009 for the course PHYSICS 7C taught by Professor Lin during the Spring '08 term at Berkeley.

### Page1 / 3

HW2Sol - Solutions to WebAssign HW#2 Giancoli Ch 32 4 13 25...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online