HW4_Solution - Problem 3.97 Known: Butane undergoes a...

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Problem 3.97 Known : Butane undergoes a process in which the relationship between pressure and specific volume is known. Find : Determine the work. : P 1 = 5 MPa T 1 = 500 K P 2 = 3 MPa T 2 = 450 K m = 5 Kg p υ n = constant Assumptions : Closed System Volume change is the only work Solution : Starting with the equation for work done by volume change, we can substitute in using the given relationship. p υ n = C Substituting in for dV and p gives us the below equation. We can then solve the integral to determine work. Substituting back in for C gives us,
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From Table A-1 We can find that M=58.12 (kg/kmol), T c = 425 (K) , and P c = 38.0 (Bar). Using Figure A-2 and the two values above we find = 0.6 Using the same analysis as above we can find . Instead of using Figure A-2 we will use Figure A-1 for because of its increased accuracy in the region that we are interested in. Before we can solve for work we have to solve for n. Using the pressure specific volume relationship we get. Now we can plug back into the original equation we derived for work to find the solution.
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Problem 3.102 Known: Pressure and Temperature of each gas. Find : Determine the applicability of the ideal gas model for each state. Given Data : a. Fluid: H 2 O State 1 T = 700 ˚F P =1600 lbf/in 2 State 2 T = 700 ˚F P =160 lbf/in 2 Solution : Method 1. Steam Tables Using Table A-4E v 1 = 0.342 ft 3 /lb
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This note was uploaded on 10/06/2009 for the course ENGRD 2210 at Cornell University (Engineering School).

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HW4_Solution - Problem 3.97 Known: Butane undergoes a...

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