BIS102 Hilt Sp03 MT2

BIS102 Hilt Sp03 MT2 - BIS 102 Spring, 2003 K. Hilt Name...

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BIS 102 Name ________________ Key _____________________ Spring, 2003 Last First K. Hilt Second Midterm Score (100): ___________ 1. (13 pts.) How many moles of O 2 will be released if a liter of blood containing 37 g of hemoglobin is transferred from 65 torr, pH 7.6 to 15 torr, pH 7.2? Hemoglobin has a molecular weight of 68,000. Show all calculations. 1. 37 g Hb/68,000 g/mol = 5.4412 x 10 -4 mol Hb (+2) 2. At 65 torr, 100% of the Hb is oxygenated. Therefore, (5.4412 x 10 -4 mol) (4) = 2.1765 x 10 -3 mol O 2 bound originally. (+2) (+1) 3. At 15 torr, pH 7.2, only 15% (+1) of the O 2 is bound to Hb. Therefore, 85% released. (+2) 4. (0.85) (2.1765 x 10 -3 mol O 2 ) = 1.85 x 10 -3 mol O 2 released (+2) (+1) (+2) 2. (20 pts.) Identify the allosteric effector that causes the shift in curves pictured in question #1. Give its complete name (i.e. positive, homotropic, etc.). Then give a detailed explanation, at the molecular level, of why the curve pictured in question #1 shifts to the right. Where does this allosteric effector bind? Why does its binding shift the curve to the right? H + (+2) is the effector. It is a negative (+2) heterotropic (+2) allosteric effector. The curve shifts to the right because several ionic bonds (+2) (salt bridges) become strengthened (+4). H + binds principally to four residues the two C-terminal histidines (+2) of the β -subunits (+2)
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This note was uploaded on 10/07/2009 for the course BIS 52192 taught by Professor Enochbaldwin during the Spring '09 term at UC Davis.

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BIS102 Hilt Sp03 MT2 - BIS 102 Spring, 2003 K. Hilt Name...

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