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Unformatted text preview: Hour Exam 1 Group Problem The sidereal rotation period of the Sun is 25.38 days at the solar equator. Because the Sun is gaseous, the rotation period can be and indeed is somewhat dierent at other parts of the Sun. However, for this problem, we will use 25.38 days as the rotation period of the Sun. The radius of the Sun is 6.96108 m. The distance from the Earth to the Sun is 1.000 Astronomical Units (A.U.) or 1.496 1011 m. The rotation period of the Earth is 1.000 days or 86400 s. The equatorial radius of the Earth is 6378.1 km. (a) What is the angular velocity of the Earth's rotation on its axis? [4 points]
earth = rad 2 rad rad 2 = 2 = = 7.27 10-5 period day 86400 s s (b) What is the angular velocity of the Earth's orbit around the sun? [4 points]
orbit = 2 rad rad 2 10-7 year s (c) What is the angular velocity of the Sun's rotation on its axis? [4 points]
sun = 2 2 rad 2 rad rad = = = 2.865 10-6 period 25.38 days 2192832 s s (d) What is the linear velocity of a point on the surface of the Earth's due to the Earth's rotation? [4 points]
v(r) = r = Rearth earth = 6378.1 7.27 10-5 km km = .463 s s (d) What is the linear velocity of a point on the Earth due to the Earth's orbital motion around the Sun? [4 points]
v(r) = r = 1AU orbit = 1.496 108 km(2 10-7 rad ) = 29.92km/s s (e) What is the acceleration of a point on the surface of the Earth at the equator due to the rotation of the Earth? How does this acceleration compare to the acceleration of gravity? [5 points]
a= v2 2 = earth Rearth = .033m/s2 r this corresponds to less than percent of the acceleration of gravity 1 ...
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This note was uploaded on 10/07/2009 for the course PHYS 1301W taught by Professor Marshak during the Fall '08 term at Minnesota.
- Fall '08