EE_387_200809SP_homework_06_solution

# EE_387_200809SP_homework_06_solution - 1 V = 8 V F = 4 N 15...

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1 Homework 06 Solution © Jeffrey Mayer 2005-2009. All rights reserved. EE 387 Spring 2009 1. 2 3 62 33 () ( ) (62.83 10 )(0.6) 2667 (4.0 10 ) 2.1kN/m ke ff f F xx x ki K x δ δδ χ −− =− =− + + × + × 012345 0 5 10 15 -f e [N] f - f K [N] x [mm] V = 8 V, F = 4 N 4.0 mm x =

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2 Homework 06 Solution © Jeffrey Mayer 2005-2009. All rights reserved. EE 387 Spring 2009 2. 02468 1 0 1 2 3 3.5 4 4.5 V [V] X [mm] F = 4 N
3 Homework 06 Solution © Jeffrey Mayer 2005-2009. All rights reserved. EE 387 Spring 2009 3. if scenario == 1 %v_function = @(t) 5*(sign(t - 0.05) - sign(t - 0.15))/2; v_function = @(t) sqrt(2)*8*sin(2*pi*60*t).*(sign(t - 0.05) - sign(t - 0.15))/2; f_function = @(t) 0; Efmax = 10; Efmin = -10; Femin = -5; Femax = 5; else v_function = @(t) 5; f_function = @(t) 4*(sign(t - 0.05) - sign(t - 0.15))/2; Efmax = 1; Efmin = -1; Femin = -3; Femax = 1; end

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4 Homework 06 Solution © Jeffrey Mayer 2005-2009. All rights reserved. EE 387 Spring 2009 3. -10 0 10 v [V] Scenario 1 -10 0 10 e f [V] -20 0 20 λ [mWb t] -1 0 1 i [A] -5 0 5 f e [N] 0 50 100 150 200 250 0 2 4 x [mm] t [ms]
5 Homework 06 Solution © Jeffrey Mayer 2005-2009. All rights reserved. EE 387 Spring 2009 s ϕ () gsa s F 1 12 s sa Ni 1 2 s sa gsa s F 1 2 s sa s 4.

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