hw11sol - STAT401 Homework 11 Solutions(Spring 2009 10.4.1...

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Unformatted text preview: STAT401: Homework 11 Solutions (Spring 2009) 10.4.1 4. (a) H : F 1 = F 2 or μ 1 = μ 2 , H A : μ 1 6 = μ 2 (b) No, because n¡30 and the data are not normally distributed (c) ( R 11 , ··· R 19 )=(18,16,12,9,7,5,2,4,14). W= ∑ j R 1 j = 87, n 1 = n 2 = 9, N = n 1 + n 2 = 18 Z H = q 12 n 1 n 2 ( N +1) ( W- n 1 N +1 2 ) = q 12 9 * 9 * 19 ( W- 9 * 19 2 ) = 0 . 132, Z . 975 = 1 . 96 Since 0 . 132 < 1 . 96, do not reject null hypothesis, and conclude that the total amplitude strain of the two graphites do not differ signifi- cantly. 10.5.3. 4. (a) H : μ D = 0 ,H a : μ D > (b) ¯ d = 1 . 71 ,S D = 0 . 617 t * = ¯ d- Δ S D / √ n = 1 . 71 . 617 / √ 10 = 8 . 76. RR = { t * : t * > t α,n- 1 } (c) Assume normal distribution. (d) t * > t . 05 , 9 =1.833. Reject. p-value= P ( t * > 8 . 76) = 0 . (e) H : μ 1- μ 2 = 0 vs H : μ 1- μ 2 > 0, ¯ x 1 = 23 . 18 , ¯ x 2 = 21 . 47 ,S 1 = 4 . 185 ,S 2 = 3 . 805 t * = ¯ x 1- ¯ x 2 r S 2 1 n 1 + S 2 2 n 2 = 23 . 18- 21 . 47 q 4 . 185 2 10 +...
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This note was uploaded on 10/08/2009 for the course STAT 401 taught by Professor Akritas during the Spring '00 term at Penn State.

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hw11sol - STAT401 Homework 11 Solutions(Spring 2009 10.4.1...

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