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Hwk1SolnGdDrtBF09

# Hwk1SolnGdDrtBF09 - Solutions to Homework I Instructor...

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A = 0.23= 0.05 F=.06 0.06 P(S) = 1.00 Solutions to Homework I, Instructor Generated Questions. Question 1. (Note: This solution is done analytically. It is far easier to draw a Venn Diagram and first determine the probabilities of every associated area in the picture, determine what those areas represent in terms of the problem, and then do the problem.) A) Let F = {Fly First Class} A={Alcohol Consumed}. Given P(F) = .11 P(A) = .28 P(F∩A) = .05. B) P(F) = Customer flys first class P( F ) = Customer doesn’t fly first class Total P(A) = Customer has an alcoholic beverage .05 .23 .28 P( A ) = Customer doesn’t have an alcoholic beverage .06 .66 .72 Total .11 .89 1 Steps: 1) Fill in the givens (in bold) 2) Calculate additional information using addition rules; the 1 st two rows should sum to the 3 rd row and the 1 st two columns should sum to the 3 rd column. All totals should sum to 1. C)

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D) P(F A) = P(F) + P(A) – P(F∩A) = .11 + .28 - .05 = .34 E) P( P(F) = P(F∩A) + P(F∩) → .11 = .05 + P(F∩) → P(F∩) = .06 So = ( ) ( )= . . = . PAF P A F P F 06 11 545 F) P( P(A) = P(A∩F) + P(A∩) → .28 = .05 + P(A∩) → P(A∩) = .23 So = ( ∩ ) ( )= . . PFA P F A P A
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