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Unformatted text preview: /35 Winter Quarter 2008 Winter Quarter 2008 Experiment: 2D collisions Your name: Anish Dundoo Partner: Jacob Schlather Performed on: February 25 th , 2008 TA: Hyundeok Song Section number: 218 Promptness % (100 means it was on time): 100 Additional Scores (+)/Penalties (): Abstract (4) This experiment was done in order to investigate the linear momentum and kinetic energy change in a two dimensional environment. A frictionless surface was created by pumping air from beneath the table onto the pucks in order to demonstrate that the change in energy before and after a collision is equal. The measured value of the total momentum before the collision resulted in 183118gcm/s and after the collision was 162518gcm/s. The energy before collision was 2939801674 Joules and after the collision resulted in 111538635 joules. Hence, the change in kinetic energy did not compare closely to what was expected from the theory. Sample Calculations (5) Calculating the change in time at each frame: = ( ) T 1flash rate Hz = . T 119 9Hz =. T 0503sec Calculating the Magnitude of pixels in 100cm: ( )= +( ) 100cm length pixels ruler x xright xleft2 yright yleft 2 = +( ) 1737 1872 53 47 2 = . 1550 01 pixels Calculating the Pixel ratio: = Pixel Aspect Ratio Magnitude of Ruler yMagnitude of Ruler x = Pixel Aspect Ratio 15621550 = . Pixel Aspect Ratio 1 007 Calculating the momentum of the puck in a given direction: = Px mvx Error: Reference source not found, 09/17/04, Error: Reference source not found Where m is mass and vx is velocity in the x direction =( ) . P 29g 84 1cmsec = . P 2439 9g cmsec Calculating the total momentum of the system for a given direction: = + PxTotal Px1 Px2 Where Px1 is the momentum for the small puck and Px2 is the momentum for the large puck, both in the x direction = . + . PxTotal 2439 9g cmsec 3709 48g cmsec = . PxTotal 1269 58g cmsec Calculating the uncertainty the total momentum in a given direction: = { } + { } uP u Px1 2 u Px2 2 Where Px1 is the momentum for small puck and Px2 is the momentum for the large puck, both in the x direction = . + . uP 10 09g cmsec2 13 3g cmsec2 = . uP 278 6g 2 cm2sec2 = . uP 16 69g cmsec Calculating the magnitude of momentum: = + P Pxtotal2 Pytotal2 = . + . P 1269 6g cmsec2 1319 6g cmsec2 = . P 3353228 32g 2 cm2sec2 = . P 1831 2g cmsec Calculating Kinetic Energy: = K 12mv2 = + K 12mv2small puck 12mv2large puck Page 2 of Word document Error: Reference source not found, 09/17/04, Error: Reference source not found Where velocity is equal to + Vx2 Vy2 =. . . + . K 5 30 1g 85 47cmsec2 4 7cmsec2...
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 Winter '09
 larrybortner
 Physics

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