{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

nla_dundooah_218

nla_dundooah_218 - 0/35 Winter Quarter 2008 Experiment Your...

This preview shows pages 1–4. Sign up to view the full content.

0 /35 Winter Quarter 2008 Experiment: Newton’s Laws of motion Your name: Anish Dundoo Partner: Joshua Sanders Performed on: 18 th February 2008 TA: Hyundeok Song Section number: 218 Promptness % (100 means it was on time): 100 Additional Scores (+)/Penalties (-): Abstract  (4)  This experiment deals with two forces. Motion on an incline and motion due to tension. A frictionless incline that imitated a frictionless surface for the incline was used for the first force of motion. We had two different carts with different masses, the small car weighing 151.7g and the second weighing 303.1g. Each of the carts had a flag at the top of them to measure the time it took to get down the incline from different distances. The flag of the small cart and the big cart were .051m with an uncertainty of .003m. A photo gate was used to clock the time of each cart and the distances varied from .01m to 2.15m with eight different distances. The small cart was timed 10 times at the same distance of 2.15m so we could get the uncertainty in the measurement of time by the photo gate. Both the carts timed and the velocity squared vs. twice the distance was plotted to get the experimental acceleration of an incline situation. This acceleration was .19±.02m/s 2 for the small cart and .0920±.012m/s 2 for the big cart. Then tension was demonstrated with the distances and time taken simultaneously but without the incline. A bob was attached to each cart to represent the tension. Again the velocity squared vs. twice the distance was plotted to give the acceleration of the masses with the small cart accelerating at .39±.05m/s 2 and the large cart at .21±.02m/s 2 . Sample Calculations  (5)    THE FOLLOWING CALCULATIONS APPLY FOR BOTH TYPES OF FORCES. Calculations for V 2 (m/s) 2 V 2 = (flag/time) 2 V 2 = (0.051meters/0.2563seconds) 2 V 2 = (0.039 m 2 /sec 2 ) V = . 0 039 m2sec2 V = 0.198 m/sec Calculating the uncertainty of velocity squared: = × × { } + { } uv2 2 v2 u flag flag2 u time time2 = ×. ×. uv2 2 040m2sec2 003 . +. . m 051m2 0015sec 2563sec2 =. × . uv2 08m2sec2 0 059 =. uv2 004m2sec2

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Error: Reference source not found, 09/17/04, Error: Reference source not found Calculating the upper boundary of the velocity squared: += + v2 v2 uv2 +=. +. v2 040m2sec2 004m2sec2 +=. v2 044m2sec2 Calculating the lower boundary of the velocity squared: -= - v2 v2 uv2 -=. -. v2 040m2sec2 004m2sec2 -=. v2 036m2sec2 Calculating 2*x (meters): 2*x = (x 2 +x 1 ) - (2*x 0 ) 2*x = (2.551meters + 2.500meters) – (2*2.150meters) 2*x = 1.45meters Calculating the uncertainty of 2*x (meters): U{2x} = 2.5 * u{x} U{2x} = 2.5 * 0.002m U{2x} = 0.005m Calculating the average time: T (avg) = (T 1 +T 2 +T 3 +…+T 10 ) / (number of trials) T (avg) = (Total) / (10) T (avg) = 0.2563 seconds Calculating the height in meters: h(m) = h(mm)/1000 h(m) = 36.3mm * 1000 Page 2 of Word document
Error: Reference source not found, 09/17/04, Error: Reference source not found h(m) = 0.0363 m THE FOLLOWING CALCULATIONS APPLY ONLY FOR THE FORCE OF GRAVITY (MOTION ON AN INCLINED PLANE)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 8

nla_dundooah_218 - 0/35 Winter Quarter 2008 Experiment Your...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online